IDNLearn.com makes it easy to find precise answers to your specific questions. Discover comprehensive answers from knowledgeable members of our community, covering a wide range of topics to meet all your informational needs.
Sagot :
Here's how you can solve the problem step-by-step. We are given that the area of the circle is two times its circumference and need to find the diameter of the circle. We'll use the formulas for the area and circumference of a circle and solve for the radius, then calculate the diameter.
1. Recall the formulas for the area and circumference of a circle:
- Area [tex]\( A \)[/tex] of a circle is given by [tex]\( A = \pi r^2 \)[/tex]
- Circumference [tex]\( C \)[/tex] of a circle is given by [tex]\( C = 2 \pi r \)[/tex]
2. Given condition: The area is two times the circumference.
[tex]\[ \pi r^2 = 2 \times (2 \pi r) \][/tex]
3. Simplify the equation:
[tex]\[ \pi r^2 = 4 \pi r \][/tex]
4. Divide both sides by [tex]\( \pi \)[/tex] (assuming [tex]\( \pi \neq 0 \)[/tex]):
[tex]\[ r^2 = 4r \][/tex]
5. Rearrange the equation to form a standard quadratic equation:
[tex]\[ r^2 - 4r = 0 \][/tex]
6. Factorize the quadratic equation:
[tex]\[ r(r - 4) = 0 \][/tex]
7. Solve for [tex]\( r \)[/tex]:
[tex]\[ r = 0 \quad \text{or} \quad r = 4 \][/tex]
Since the radius cannot be zero, we discard [tex]\( r = 0 \)[/tex].
Therefore, [tex]\( r = 4 \)[/tex] cm.
8. Calculate the diameter of the circle:
The diameter [tex]\( d \)[/tex] is twice the radius.
[tex]\[ d = 2r = 2 \times 4 = 8 \, \text{cm} \][/tex]
Thus, the diameter of the circle is [tex]\( 8 \)[/tex] cm.
1. Recall the formulas for the area and circumference of a circle:
- Area [tex]\( A \)[/tex] of a circle is given by [tex]\( A = \pi r^2 \)[/tex]
- Circumference [tex]\( C \)[/tex] of a circle is given by [tex]\( C = 2 \pi r \)[/tex]
2. Given condition: The area is two times the circumference.
[tex]\[ \pi r^2 = 2 \times (2 \pi r) \][/tex]
3. Simplify the equation:
[tex]\[ \pi r^2 = 4 \pi r \][/tex]
4. Divide both sides by [tex]\( \pi \)[/tex] (assuming [tex]\( \pi \neq 0 \)[/tex]):
[tex]\[ r^2 = 4r \][/tex]
5. Rearrange the equation to form a standard quadratic equation:
[tex]\[ r^2 - 4r = 0 \][/tex]
6. Factorize the quadratic equation:
[tex]\[ r(r - 4) = 0 \][/tex]
7. Solve for [tex]\( r \)[/tex]:
[tex]\[ r = 0 \quad \text{or} \quad r = 4 \][/tex]
Since the radius cannot be zero, we discard [tex]\( r = 0 \)[/tex].
Therefore, [tex]\( r = 4 \)[/tex] cm.
8. Calculate the diameter of the circle:
The diameter [tex]\( d \)[/tex] is twice the radius.
[tex]\[ d = 2r = 2 \times 4 = 8 \, \text{cm} \][/tex]
Thus, the diameter of the circle is [tex]\( 8 \)[/tex] cm.
Thank you for using this platform to share and learn. Keep asking and answering. We appreciate every contribution you make. Your search for answers ends at IDNLearn.com. Thank you for visiting, and we hope to assist you again soon.