Find solutions to your problems with the help of IDNLearn.com's knowledgeable users. Our platform is designed to provide trustworthy and thorough answers to any questions you may have.

To solve the system of equations below, Zach isolated [tex]\(x^2\)[/tex] in the first equation and then substituted it into the second equation. What was the resulting equation?

[tex]\[
\left\{\begin{array}{l}
x^2 + y^2 = 25 \\
\frac{x^2}{16} - \frac{y^2}{9} = 1
\end{array}\right.
\][/tex]

A. [tex]\(\frac{x^2}{16} - \frac{y^2 - 25}{9} = 1\)[/tex]

B. [tex]\(\frac{y^2 - 25}{16} - \frac{y^2}{9} = 1\)[/tex]

C. [tex]\(\frac{x^2}{16} - \frac{25 - y^2}{9} = 1\)[/tex]

D. [tex]\(\frac{25 - y^2}{16} - \frac{y^2}{9} = 1\)[/tex]


Sagot :

To solve the given system of equations, we can follow the logical steps to isolate [tex]\( x^2 \)[/tex] in the first equation and then substitute it into the second equation to find the resulting equation.

Given the system of equations:
[tex]\[ \left\{\begin{array}{l} x^2 + y^2 = 25 \\ \frac{x^2}{16} - \frac{y^2}{9} = 1 \end{array}\right. \][/tex]

Let's begin by isolating [tex]\( x^2 \)[/tex] in the first equation:
[tex]\[ x^2 + y^2 = 25 \][/tex]

Rearrange to solve for [tex]\( x^2 \)[/tex]:
[tex]\[ x^2 = 25 - y^2 \][/tex]

Now we substitute this expression for [tex]\( x^2 \)[/tex] into the second equation:
[tex]\[ \frac{x^2}{16} - \frac{y^2}{9} = 1 \][/tex]

Substituting [tex]\( x^2 = 25 - y^2 \)[/tex] into the second equation gives us:
[tex]\[ \frac{25 - y^2}{16} - \frac{y^2}{9} = 1 \][/tex]

This is the resulting equation after substituting [tex]\( x^2 \)[/tex] from the first equation into the second equation.

Thus, the correct choice is:
[tex]\[ \boxed{\frac{25 - y^2}{16} - \frac{y^2}{9} = 1} \][/tex]

The corresponding option from the given choices is:
[tex]\[ D. \frac{25 - y^2}{16} - \frac{y^2}{9} = 1 \][/tex]