IDNLearn.com: Your trusted platform for finding reliable answers. Our platform offers detailed and accurate responses from experts, helping you navigate any topic with confidence.
Sagot :
To determine which reactions have an increase in entropy, we consider the change in the number of moles of gas during the reaction. The change in entropy is generally related to the change in the number of gas molecules; if the number of gas molecules increases, the entropy of the system typically increases.
Let's go through each reaction step by step:
### Reaction A:
[tex]\[ 2 \, \text{CO (g)} + 2 \, \text{NO (g)} \rightarrow 2 \, \text{CO}_2 \, \text{(g)} + \text{N}_2 \, \text{(g)} \][/tex]
Calculate the change in the number of gas moles:
- Reactants: [tex]\(2 \, \text{CO (g)} + 2 \, \text{NO (g)} = 4\)[/tex] moles of gas
- Products: [tex]\(2 \, \text{CO}_2 \, \text{(g)} + \text{N}_2 \, \text{(g)} = 3\)[/tex] moles of gas
Change in moles: [tex]\(3 - 4 = -1\)[/tex]
### Reaction B:
[tex]\[ 2 \, \text{H}_2\text{S (g)} + 3 \, \text{O}_2 \, \text{(g)} \rightarrow 2 \, \text{H}_2\text{O (g)} + 2 \, \text{SO}_2 \, \text{(g)} \][/tex]
Calculate the change in the number of gas moles:
- Reactants: [tex]\(2 \, \text{H}_2\text{S (g)} + 3 \, \text{O}_2 \, \text{(g)} = 5\)[/tex] moles of gas
- Products: [tex]\(2 \, \text{H}_2\text{O (g)} + 2 \, \text{SO}_2 \, \text{(g)} = 4\)[/tex] moles of gas
Change in moles: [tex]\(4 - 5 = -1\)[/tex]
### Reaction C:
[tex]\[ \text{CH}_4 \, \text{(g)} + \text{H}_2\text{O (g)} \rightarrow \text{CO (g)} + 3 \, \text{H}_2 \, \text{(g)} \][/tex]
Calculate the change in the number of gas moles:
- Reactants: [tex]\(\text{CH}_4 \, \text{(g)} + \text{H}_2\text{O (g)} = 2\)[/tex] moles of gas
- Products: [tex]\(\text{CO (g)} + 3 \, \text{H}_2 \, \text{(g)} = 4\)[/tex] moles of gas
Change in moles: [tex]\(4 - 2 = 2\)[/tex]
### Reaction D:
[tex]\[ 2 \, \text{NO (g)} + 2 \, \text{H}_2 \, \text{(g)} \rightarrow \text{N}_2 \, \text{(g)} + 2 \, \text{H}_2\text{O (g)} \][/tex]
Calculate the change in the number of gas moles:
- Reactants: [tex]\(2 \, \text{NO (g)} + 2 \, \text{H}_2 \, \text{(g)} = 4\)[/tex] moles of gas
- Products: [tex]\(\text{N}_2 \, \text{(g)} + 2 \, \text{H}_2\text{O (g)} = 3\)[/tex] moles of gas
Change in moles: [tex]\(3 - 4 = -1\)[/tex]
### Summary:
- Reaction A: Change in moles = -1 (Decrease in entropy)
- Reaction B: Change in moles = -1 (Decrease in entropy)
- Reaction C: Change in moles = 2 (Increase in entropy)
- Reaction D: Change in moles = -1 (Decrease in entropy)
Thus, the reaction with an increase in entropy is Reaction C:
[tex]\[ \text{CH}_4 \, \text{(g)} + \text{H}_2\text{O (g)} \rightarrow \text{CO (g)} + 3 \, \text{H}_2 \, \text{(g)} \][/tex]
Let's go through each reaction step by step:
### Reaction A:
[tex]\[ 2 \, \text{CO (g)} + 2 \, \text{NO (g)} \rightarrow 2 \, \text{CO}_2 \, \text{(g)} + \text{N}_2 \, \text{(g)} \][/tex]
Calculate the change in the number of gas moles:
- Reactants: [tex]\(2 \, \text{CO (g)} + 2 \, \text{NO (g)} = 4\)[/tex] moles of gas
- Products: [tex]\(2 \, \text{CO}_2 \, \text{(g)} + \text{N}_2 \, \text{(g)} = 3\)[/tex] moles of gas
Change in moles: [tex]\(3 - 4 = -1\)[/tex]
### Reaction B:
[tex]\[ 2 \, \text{H}_2\text{S (g)} + 3 \, \text{O}_2 \, \text{(g)} \rightarrow 2 \, \text{H}_2\text{O (g)} + 2 \, \text{SO}_2 \, \text{(g)} \][/tex]
Calculate the change in the number of gas moles:
- Reactants: [tex]\(2 \, \text{H}_2\text{S (g)} + 3 \, \text{O}_2 \, \text{(g)} = 5\)[/tex] moles of gas
- Products: [tex]\(2 \, \text{H}_2\text{O (g)} + 2 \, \text{SO}_2 \, \text{(g)} = 4\)[/tex] moles of gas
Change in moles: [tex]\(4 - 5 = -1\)[/tex]
### Reaction C:
[tex]\[ \text{CH}_4 \, \text{(g)} + \text{H}_2\text{O (g)} \rightarrow \text{CO (g)} + 3 \, \text{H}_2 \, \text{(g)} \][/tex]
Calculate the change in the number of gas moles:
- Reactants: [tex]\(\text{CH}_4 \, \text{(g)} + \text{H}_2\text{O (g)} = 2\)[/tex] moles of gas
- Products: [tex]\(\text{CO (g)} + 3 \, \text{H}_2 \, \text{(g)} = 4\)[/tex] moles of gas
Change in moles: [tex]\(4 - 2 = 2\)[/tex]
### Reaction D:
[tex]\[ 2 \, \text{NO (g)} + 2 \, \text{H}_2 \, \text{(g)} \rightarrow \text{N}_2 \, \text{(g)} + 2 \, \text{H}_2\text{O (g)} \][/tex]
Calculate the change in the number of gas moles:
- Reactants: [tex]\(2 \, \text{NO (g)} + 2 \, \text{H}_2 \, \text{(g)} = 4\)[/tex] moles of gas
- Products: [tex]\(\text{N}_2 \, \text{(g)} + 2 \, \text{H}_2\text{O (g)} = 3\)[/tex] moles of gas
Change in moles: [tex]\(3 - 4 = -1\)[/tex]
### Summary:
- Reaction A: Change in moles = -1 (Decrease in entropy)
- Reaction B: Change in moles = -1 (Decrease in entropy)
- Reaction C: Change in moles = 2 (Increase in entropy)
- Reaction D: Change in moles = -1 (Decrease in entropy)
Thus, the reaction with an increase in entropy is Reaction C:
[tex]\[ \text{CH}_4 \, \text{(g)} + \text{H}_2\text{O (g)} \rightarrow \text{CO (g)} + 3 \, \text{H}_2 \, \text{(g)} \][/tex]
We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Find reliable answers at IDNLearn.com. Thanks for stopping by, and come back for more trustworthy solutions.
