IDNLearn.com offers a unique blend of expert answers and community-driven knowledge. Get the information you need from our experts, who provide reliable and detailed answers to all your questions.
Sagot :
To determine the probability [tex]\( P(A, D) \)[/tex] where two cards are drawn with replacement from a set that spells out the word "ADD," we can follow these detailed steps:
1. Identify the Card Set and Probabilities:
- The set of cards includes: A, D, D.
- The total number of cards is 3.
2. Define the Probabilities for Each Event:
- Probability of drawing an 'A' (P(A)): Since there is only 1 'A' card out of 3 cards:
[tex]\[ P(A) = \frac{1}{3} \][/tex]
- Probability of drawing a 'D' (P(D)): Since there are 2 'D' cards out of 3 cards:
[tex]\[ P(D) = \frac{2}{3} \][/tex]
3. Calculate the Probability of Drawing 'A' first and then 'D':
[tex]\[ P(A \text{ then } D) = P(A) \times P(D) = \frac{1}{3} \times \frac{2}{3} = \frac{2}{9} \][/tex]
4. Calculate the Probability of Drawing 'D' first and then 'A':
[tex]\[ P(D \text{ then } A) = P(D) \times P(A) = \frac{2}{3} \times \frac{1}{3} = \frac{2}{9} \][/tex]
5. Calculate the Combined Probability for Either Scenario:
Since [tex]\( P(A, D) \)[/tex] includes both scenarios where 'D' is the second card (either drawing 'A' first followed by 'D' or drawing 'D' first followed by 'A'):
[tex]\[ P(A, D) = P(A \text{ then } D) + P(D \text{ then } A) = \frac{2}{9} + \frac{2}{9} = \frac{4}{9} \][/tex]
Thus, the probability [tex]\( P(A, D) \)[/tex] is [tex]\(\frac{4}{9}\)[/tex].
Therefore, the correct answer is [tex]\(\frac{4}{9}\)[/tex].
1. Identify the Card Set and Probabilities:
- The set of cards includes: A, D, D.
- The total number of cards is 3.
2. Define the Probabilities for Each Event:
- Probability of drawing an 'A' (P(A)): Since there is only 1 'A' card out of 3 cards:
[tex]\[ P(A) = \frac{1}{3} \][/tex]
- Probability of drawing a 'D' (P(D)): Since there are 2 'D' cards out of 3 cards:
[tex]\[ P(D) = \frac{2}{3} \][/tex]
3. Calculate the Probability of Drawing 'A' first and then 'D':
[tex]\[ P(A \text{ then } D) = P(A) \times P(D) = \frac{1}{3} \times \frac{2}{3} = \frac{2}{9} \][/tex]
4. Calculate the Probability of Drawing 'D' first and then 'A':
[tex]\[ P(D \text{ then } A) = P(D) \times P(A) = \frac{2}{3} \times \frac{1}{3} = \frac{2}{9} \][/tex]
5. Calculate the Combined Probability for Either Scenario:
Since [tex]\( P(A, D) \)[/tex] includes both scenarios where 'D' is the second card (either drawing 'A' first followed by 'D' or drawing 'D' first followed by 'A'):
[tex]\[ P(A, D) = P(A \text{ then } D) + P(D \text{ then } A) = \frac{2}{9} + \frac{2}{9} = \frac{4}{9} \][/tex]
Thus, the probability [tex]\( P(A, D) \)[/tex] is [tex]\(\frac{4}{9}\)[/tex].
Therefore, the correct answer is [tex]\(\frac{4}{9}\)[/tex].
We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. IDNLearn.com provides the best answers to your questions. Thank you for visiting, and come back soon for more helpful information.