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Solve the system of equations:
[tex]\[ \begin{cases} 4x - 6y = -6 \\ 8x + 3y = -7 \end{cases} \][/tex]


Sagot :

To solve the system of linear equations

[tex]\[ \begin{cases} 4x - 6y = -6 \\ 8x + 3y = -7 \end{cases} \][/tex]

we follow these steps:

1. Equation Rearrangement:

We already have the system in standard form [tex]\(Ax + By = C\)[/tex]. We can start solving it by any preferred method such as substitution or elimination.

2. Elimination Method:

We aim to eliminate one of the variables by adding or subtracting the equations. First, let's multiply the first equation by 2 to align the coefficients of [tex]\(x\)[/tex] in both equations.

[tex]\[ 2 \times (4x - 6y) = 2 \times (-6) \][/tex]

This simplifies to:

[tex]\[ 8x - 12y = -12 \][/tex]

Now we have:

[tex]\[ \begin{cases} 8x - 12y = -12 \\ 8x + 3y = -7 \end{cases} \][/tex]

3. Subtract the Second Equation from the First:

[tex]\[ (8x - 12y) - (8x + 3y) = -12 - (-7) \][/tex]

Simplify this:

[tex]\[ 8x - 12y - 8x - 3y = -12 + 7 \][/tex]

[tex]\[ -15y = -5 \][/tex]

Solving for [tex]\(y\)[/tex]:

[tex]\[ y = \frac{-5}{-15} = \frac{1}{3} \][/tex]

4. Substitute [tex]\(y\)[/tex] back into one of the original equations to solve for [tex]\(x\)[/tex]:

Let's use the first equation [tex]\(4x - 6y = -6\)[/tex]:

[tex]\[ 4x - 6 \left(\frac{1}{3}\right) = -6 \][/tex]

Simplify the equation:

[tex]\[ 4x - 2 = -6 \][/tex]

Add 2 to both sides:

[tex]\[ 4x = -6 + 2 \][/tex]

[tex]\[ 4x = -4 \][/tex]

Solve for [tex]\(x\)[/tex]:

[tex]\[ x = \frac{-4}{4} = -1 \][/tex]

Therefore, the solution to the system of equations is:

[tex]\[ (x, y) = \left(-1, \frac{1}{3}\right) \][/tex]