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The scores from 50 psychology students who took a standardized test are summarized in the table below:

[tex]\[
\begin{tabular}{|c|c|}
\hline
Scores & Frequency \\
\hline
80-89 & 9 \\
\hline
90-99 & 6 \\
\hline
100-109 & 7 \\
\hline
110-119 & 9 \\
\hline
120-129 & 19 \\
\hline
\end{tabular}
\][/tex]

If a relative frequency distribution is constructed for this data set, what is the relative frequency for the first class, 80-89? Round the answer to two decimal places.

Relative frequency [tex]$=$[/tex] [tex]$\square$[/tex]

Sagot :

GinnyAnsweridn
To find the relative frequency for the first class (80-89), follow these steps:

1. Identify the frequency of the first class: According to the table, the frequency for the score range 80-89 is 9.

2. Determine the total number of students: The total number of students is given as 50.

3. Calculate the relative frequency: The relative frequency is found by dividing the frequency of the first class by the total number of students.
[tex]\[ \text{Relative Frequency} = \frac{\text{Frequency of the first class}}{\text{Total number of students}} = \frac{9}{50} \][/tex]

4. Compute and round the relative frequency:
[tex]\[ \frac{9}{50} = 0.18 \][/tex]
Rounding to two decimal places, the result is 0.18.

5. Conclusion: Hence, the relative frequency for the first class (80-89) is 0.18.

[tex]\[ \text{Relative frequency} = 0.18 \][/tex]
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