Join the conversation on IDNLearn.com and get the answers you seek from experts. Discover reliable answers to your questions with our extensive database of expert knowledge.
Sagot :
To find the coordinates of point [tex]\( M \)[/tex] that partitions the segment with endpoints [tex]\( X(1, -2) \)[/tex] and [tex]\( Y(10, 3) \)[/tex] in a [tex]\( 5:1 \)[/tex] ratio, we can use the section formula in coordinate geometry. Here are the detailed steps to solve this problem:
1. Identify the given points and the ratio:
- Endpoint [tex]\( X \)[/tex] has coordinates [tex]\( (x_1, y_1) = (1, -2) \)[/tex].
- Endpoint [tex]\( Y \)[/tex] has coordinates [tex]\( (x_2, y_2) = (10, 3) \)[/tex].
- The ratio for partitioning is [tex]\( m:n = 5:1 \)[/tex].
2. Write down the section formula:
The section formula for the coordinates of a point [tex]\( M(x_m, y_m) \)[/tex] dividing the segment [tex]\( XY \)[/tex] in the ratio [tex]\( m:n \)[/tex] is given by:
[tex]\[ x_m = \frac{m \cdot x_2 + n \cdot x_1}{m + n} \][/tex]
[tex]\[ y_m = \frac{m \cdot y_2 + n \cdot y_1}{m + n} \][/tex]
3. Substitute the values into the section formula:
- [tex]\( x_1 = 1 \)[/tex]
- [tex]\( y_1 = -2 \)[/tex]
- [tex]\( x_2 = 10 \)[/tex]
- [tex]\( y_2 = 3 \)[/tex]
- [tex]\( m = 5 \)[/tex]
- [tex]\( n = 1 \)[/tex]
Using these values, we can calculate each coordinate of [tex]\( M \)[/tex] separately:
4. Calculate the [tex]\( x \)[/tex]-coordinate ([tex]\( x_m \)[/tex]):
[tex]\[ x_m = \frac{5 \cdot 10 + 1 \cdot 1}{5 + 1} \][/tex]
[tex]\[ x_m = \frac{50 + 1}{6} \][/tex]
[tex]\[ x_m = \frac{51}{6} \approx 8.5 \][/tex]
5. Calculate the [tex]\( y \)[/tex]-coordinate ([tex]\( y_m \)[/tex]):
[tex]\[ y_m = \frac{5 \cdot 3 + 1 \cdot (-2)}{5 + 1} \][/tex]
[tex]\[ y_m = \frac{15 - 2}{6} \][/tex]
[tex]\[ y_m = \frac{13}{6} \approx 2.1666666666666665 \][/tex]
6. Write down the coordinates of point [tex]\( M \)[/tex]:
- Thus, the coordinates of point [tex]\( M \)[/tex] are approximately [tex]\( (8.5, 2.1666666666666665) \)[/tex].
Therefore, the point [tex]\( M \)[/tex] that partitions the segment [tex]\( XY \)[/tex] in a [tex]\( 5:1 \)[/tex] ratio has coordinates [tex]\( (8.5, 2.1666666666666665) \)[/tex].
1. Identify the given points and the ratio:
- Endpoint [tex]\( X \)[/tex] has coordinates [tex]\( (x_1, y_1) = (1, -2) \)[/tex].
- Endpoint [tex]\( Y \)[/tex] has coordinates [tex]\( (x_2, y_2) = (10, 3) \)[/tex].
- The ratio for partitioning is [tex]\( m:n = 5:1 \)[/tex].
2. Write down the section formula:
The section formula for the coordinates of a point [tex]\( M(x_m, y_m) \)[/tex] dividing the segment [tex]\( XY \)[/tex] in the ratio [tex]\( m:n \)[/tex] is given by:
[tex]\[ x_m = \frac{m \cdot x_2 + n \cdot x_1}{m + n} \][/tex]
[tex]\[ y_m = \frac{m \cdot y_2 + n \cdot y_1}{m + n} \][/tex]
3. Substitute the values into the section formula:
- [tex]\( x_1 = 1 \)[/tex]
- [tex]\( y_1 = -2 \)[/tex]
- [tex]\( x_2 = 10 \)[/tex]
- [tex]\( y_2 = 3 \)[/tex]
- [tex]\( m = 5 \)[/tex]
- [tex]\( n = 1 \)[/tex]
Using these values, we can calculate each coordinate of [tex]\( M \)[/tex] separately:
4. Calculate the [tex]\( x \)[/tex]-coordinate ([tex]\( x_m \)[/tex]):
[tex]\[ x_m = \frac{5 \cdot 10 + 1 \cdot 1}{5 + 1} \][/tex]
[tex]\[ x_m = \frac{50 + 1}{6} \][/tex]
[tex]\[ x_m = \frac{51}{6} \approx 8.5 \][/tex]
5. Calculate the [tex]\( y \)[/tex]-coordinate ([tex]\( y_m \)[/tex]):
[tex]\[ y_m = \frac{5 \cdot 3 + 1 \cdot (-2)}{5 + 1} \][/tex]
[tex]\[ y_m = \frac{15 - 2}{6} \][/tex]
[tex]\[ y_m = \frac{13}{6} \approx 2.1666666666666665 \][/tex]
6. Write down the coordinates of point [tex]\( M \)[/tex]:
- Thus, the coordinates of point [tex]\( M \)[/tex] are approximately [tex]\( (8.5, 2.1666666666666665) \)[/tex].
Therefore, the point [tex]\( M \)[/tex] that partitions the segment [tex]\( XY \)[/tex] in a [tex]\( 5:1 \)[/tex] ratio has coordinates [tex]\( (8.5, 2.1666666666666665) \)[/tex].
We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. For clear and precise answers, choose IDNLearn.com. Thanks for stopping by, and come back soon for more valuable insights.