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Now that you have [tex]\(x^2 - 8x + 16 = 9 + 16\)[/tex], apply the square root property to the equation.

A. [tex]\((x - 4)^2 = 25\)[/tex]
B. [tex]\((x + 16)^2 = 25\)[/tex]
C. [tex]\((x - 4)^2 = 9\)[/tex]
D. [tex]\((x + 16)^2 = 9\)[/tex]


Sagot :

Let's focus on the correct interpretation of the given equation. The given equation simplifies to:

[tex]\[ (x - 4)^2 = 9 \][/tex]

This is a classic case of the square root property. Let's solve it step by step.

1. Equation to solve:
[tex]\[ (x - 4)^2 = 9 \][/tex]

2. Apply the square root property:

When you have an equation in the form [tex]\((a)^2 = b\)[/tex], you can solve for [tex]\(a\)[/tex] by taking the square root of both sides. However, remember that taking the square root leads to two solutions, one positive and one negative.

Therefore:
[tex]\[ x - 4 = \pm\sqrt{9} \][/tex]

3. Simplify the square root:

We know that [tex]\(\sqrt{9} = 3\)[/tex]. So, the equation becomes:
[tex]\[ x - 4 = \pm 3 \][/tex]

4. Consider the two cases:

Case 1:
[tex]\[ x - 4 = 3 \][/tex]
[tex]\[ x = 4 + 3 \][/tex]
[tex]\[ x = 7 \][/tex]

Case 2:
[tex]\[ x - 4 = -3 \][/tex]
[tex]\[ x = 4 - 3 \][/tex]
[tex]\[ x = 1 \][/tex]

So, the two solutions to the equation [tex]\((x - 4)^2 = 9\)[/tex] are:
[tex]\[ x = 7 \][/tex] and [tex]\[ x = 1 \][/tex]

Conclusively, the solutions for the given equation [tex]\((x - 4)^2 = 9\)[/tex] are:
[tex]\[ x = 7 \, \text{and} \, x = 1 \][/tex]
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