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In 2008, the population of Honduras was about 7,600,000 people, growing at a rate of 2% per year, compounded continuously. Assuming the growth rate remains constant:

a) What is the equation for the population after [tex]\( t \)[/tex] years?

Fill in the blanks (if you do not know the value, write "?"):

[tex]\[ A(t) = P e^{rt} \][/tex]

- [tex]\( P = \)[/tex] [tex]\(\square\)[/tex]
- [tex]\( r = \)[/tex] [tex]\(\square\)[/tex]
- [tex]\( t = \)[/tex] [tex]\(\square\)[/tex]


Sagot :

To determine the equation for the population after [tex]\( t \)[/tex] years, we use the formula for continuous growth which is given by:

[tex]\[ A(t) = P e^{rt} \][/tex]

where:
- [tex]\( A(t) \)[/tex] is the population after [tex]\( t \)[/tex] years,
- [tex]\( P \)[/tex] is the initial population,
- [tex]\( r \)[/tex] is the growth rate, and
- [tex]\( t \)[/tex] is the time in years.

From the problem, we have the following given values:
- The initial population [tex]\( P \)[/tex] is 7,600,000.
- The growth rate [tex]\( r \)[/tex] is 2%, which we convert to a decimal by dividing by 100 to get 0.02.
- The time [tex]\( t \)[/tex] is variable and not specified.

So we can fill in the blanks as follows:

[tex]\[ \begin{array}{l} A(t) = P e^{rt}, \\ P = 7600000 \end{array} \][/tex]

[tex]\[ r = 0.02 \][/tex]

[tex]\[ t = ? \][/tex]

Therefore, the completed information is:
- Blank 1: 7600000
- Blank 2: 0.02
- Blank 3: ?

This gives us the equation for the population after [tex]\( t \)[/tex] years:

[tex]\[ A(t) = 7600000 \cdot e^{0.02t} \][/tex]

That's the equation that models the population growth of Honduras assuming the growth rate stays constant.