Solve your doubts and expand your knowledge with IDNLearn.com's extensive Q&A database. Discover prompt and accurate responses from our experts, ensuring you get the information you need quickly.
Sagot :
Let's solve each part step by step.
### Part (a)
Given:
- [tex]\( a = 3 \)[/tex]
- [tex]\( b = 1 \)[/tex]
- [tex]\( c = 2 \)[/tex]
- [tex]\( m = 3 \)[/tex]
- [tex]\( n = 4 \)[/tex]
We need to find the value of:
[tex]\[ \frac{a^m \times b^n \times c^n}{m^2 \times m^5 \times (m \cdot n)^6} \][/tex]
First, calculate the numerator:
[tex]\[ a^m \times b^n \times c^n \][/tex]
Substitute the given values:
[tex]\[ 3^3 \times 1^4 \times 2^4 \][/tex]
Evaluate the powers:
[tex]\[ 27 \times 1 \times 16 \][/tex]
Now, multiply these results:
[tex]\[ 27 \times 16 = 432 \][/tex]
Next, calculate the denominator:
[tex]\[ m^2 \times m^5 \times (m \cdot n)^6 \][/tex]
Substitute the given values:
[tex]\[ 3^2 \times 3^5 \times (3 \times 4)^6 \][/tex]
Evaluate the powers:
[tex]\[ 9 \times 243 \times (12)^6 \][/tex]
Calculate [tex]\( (12)^6 \)[/tex]:
[tex]\[ 12^6 = 2985984 \][/tex]
Now, multiply these results:
[tex]\[ 9 \times 243 \times 2985984 = 6530347008 \][/tex]
Finally, divide the numerator by the denominator:
[tex]\[ \frac{432}{6530347008} \approx 6.61526867516808 \times 10^{-8} \][/tex]
So the value of part (a) is approximately:
[tex]\[ 6.61526867516808 \times 10^{-8} \][/tex]
### Part (b)
Given the same values, we now need to find:
[tex]\[ \frac{(a+b-c)^{m+n}}{(n-m)^{-b+c}} \][/tex]
Substitute the given values:
[tex]\[ \frac{(3 + 1 - 2)^{3+4}}{(4 - 3)^{-1+2}} \][/tex]
Simplify inside the parentheses:
[tex]\[ \frac{(2)^7}{(1)^1} \][/tex]
Evaluate the powers:
[tex]\[ \frac{128}{1} \][/tex]
So the value of part (b) is:
[tex]\[ 128 \][/tex]
In summary:
- Part (a): [tex]\( 6.61526867516808 \times 10^{-8} \)[/tex]
- Part (b): [tex]\( 128 \)[/tex]
### Part (a)
Given:
- [tex]\( a = 3 \)[/tex]
- [tex]\( b = 1 \)[/tex]
- [tex]\( c = 2 \)[/tex]
- [tex]\( m = 3 \)[/tex]
- [tex]\( n = 4 \)[/tex]
We need to find the value of:
[tex]\[ \frac{a^m \times b^n \times c^n}{m^2 \times m^5 \times (m \cdot n)^6} \][/tex]
First, calculate the numerator:
[tex]\[ a^m \times b^n \times c^n \][/tex]
Substitute the given values:
[tex]\[ 3^3 \times 1^4 \times 2^4 \][/tex]
Evaluate the powers:
[tex]\[ 27 \times 1 \times 16 \][/tex]
Now, multiply these results:
[tex]\[ 27 \times 16 = 432 \][/tex]
Next, calculate the denominator:
[tex]\[ m^2 \times m^5 \times (m \cdot n)^6 \][/tex]
Substitute the given values:
[tex]\[ 3^2 \times 3^5 \times (3 \times 4)^6 \][/tex]
Evaluate the powers:
[tex]\[ 9 \times 243 \times (12)^6 \][/tex]
Calculate [tex]\( (12)^6 \)[/tex]:
[tex]\[ 12^6 = 2985984 \][/tex]
Now, multiply these results:
[tex]\[ 9 \times 243 \times 2985984 = 6530347008 \][/tex]
Finally, divide the numerator by the denominator:
[tex]\[ \frac{432}{6530347008} \approx 6.61526867516808 \times 10^{-8} \][/tex]
So the value of part (a) is approximately:
[tex]\[ 6.61526867516808 \times 10^{-8} \][/tex]
### Part (b)
Given the same values, we now need to find:
[tex]\[ \frac{(a+b-c)^{m+n}}{(n-m)^{-b+c}} \][/tex]
Substitute the given values:
[tex]\[ \frac{(3 + 1 - 2)^{3+4}}{(4 - 3)^{-1+2}} \][/tex]
Simplify inside the parentheses:
[tex]\[ \frac{(2)^7}{(1)^1} \][/tex]
Evaluate the powers:
[tex]\[ \frac{128}{1} \][/tex]
So the value of part (b) is:
[tex]\[ 128 \][/tex]
In summary:
- Part (a): [tex]\( 6.61526867516808 \times 10^{-8} \)[/tex]
- Part (b): [tex]\( 128 \)[/tex]
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com is committed to providing the best answers. Thank you for visiting, and see you next time for more solutions.