Discover new knowledge and insights with IDNLearn.com's extensive Q&A platform. Get the information you need from our experts, who provide reliable and detailed answers to all your questions.
Sagot :
Let's break down the solution step-by-step for each part of the problem.
### 1. Bill's Acceleration
1. Initial Velocity of Bill: [tex]\( u = 7 \, \text{m/s} \)[/tex]
2. Final Velocity of Bill: [tex]\( v = 19 \, \text{m/s} \)[/tex]
3. Time taken by Bill: [tex]\( t = 5 \, \text{seconds} \)[/tex]
The formula for acceleration ([tex]\( a \)[/tex]) is:
[tex]\[ a = \frac{v - u}{t} \][/tex]
Substituting the values:
[tex]\[ a = \frac{19 - 7}{5} \][/tex]
[tex]\[ a = \frac{12}{5} \][/tex]
[tex]\[ a = 2.4 \, \text{m/s}^2 \][/tex]
So, Bill's acceleration is [tex]\( 2.4 \, \text{m/s}^2 \)[/tex].
### 2. Ben's Acceleration
1. Initial Velocity of Ben: [tex]\( u = 15 \, \text{m/s} \)[/tex]
2. Final Velocity of Ben: [tex]\( v = 21 \, \text{m/s} \)[/tex]
3. Time taken by Ben: [tex]\( t = 7 \, \text{seconds} \)[/tex]
Using the formula for acceleration ([tex]\( a \)[/tex]):
[tex]\[ a = \frac{v - u}{t} \][/tex]
Substituting the values:
[tex]\[ a = \frac{21 - 15}{7} \][/tex]
[tex]\[ a = \frac{6}{7} \][/tex]
[tex]\[ a \approx 0.8571 \, \text{m/s}^2 \][/tex]
So, Ben's acceleration is approximately [tex]\( 0.8571 \, \text{m/s}^2 \)[/tex].
### 3. Faster Velocity
To determine who is traveling at a faster velocity, we compare the final velocities of Bill and Ben.
- Bill's final velocity: [tex]\( 19 \, \text{m/s} \)[/tex]
- Ben's final velocity: [tex]\( 21 \, \text{m/s} \)[/tex]
Ben's final velocity is higher than Bill's.
Therefore, Ben is traveling at a faster velocity.
### Summary
1. Bill's acceleration is [tex]\( 2.4 \, \text{m/s}^2 \)[/tex].
2. Ben's acceleration is approximately [tex]\( 0.8571 \, \text{m/s}^2 \)[/tex].
3. Ben is traveling at a faster velocity (21 m/s).
### 1. Bill's Acceleration
1. Initial Velocity of Bill: [tex]\( u = 7 \, \text{m/s} \)[/tex]
2. Final Velocity of Bill: [tex]\( v = 19 \, \text{m/s} \)[/tex]
3. Time taken by Bill: [tex]\( t = 5 \, \text{seconds} \)[/tex]
The formula for acceleration ([tex]\( a \)[/tex]) is:
[tex]\[ a = \frac{v - u}{t} \][/tex]
Substituting the values:
[tex]\[ a = \frac{19 - 7}{5} \][/tex]
[tex]\[ a = \frac{12}{5} \][/tex]
[tex]\[ a = 2.4 \, \text{m/s}^2 \][/tex]
So, Bill's acceleration is [tex]\( 2.4 \, \text{m/s}^2 \)[/tex].
### 2. Ben's Acceleration
1. Initial Velocity of Ben: [tex]\( u = 15 \, \text{m/s} \)[/tex]
2. Final Velocity of Ben: [tex]\( v = 21 \, \text{m/s} \)[/tex]
3. Time taken by Ben: [tex]\( t = 7 \, \text{seconds} \)[/tex]
Using the formula for acceleration ([tex]\( a \)[/tex]):
[tex]\[ a = \frac{v - u}{t} \][/tex]
Substituting the values:
[tex]\[ a = \frac{21 - 15}{7} \][/tex]
[tex]\[ a = \frac{6}{7} \][/tex]
[tex]\[ a \approx 0.8571 \, \text{m/s}^2 \][/tex]
So, Ben's acceleration is approximately [tex]\( 0.8571 \, \text{m/s}^2 \)[/tex].
### 3. Faster Velocity
To determine who is traveling at a faster velocity, we compare the final velocities of Bill and Ben.
- Bill's final velocity: [tex]\( 19 \, \text{m/s} \)[/tex]
- Ben's final velocity: [tex]\( 21 \, \text{m/s} \)[/tex]
Ben's final velocity is higher than Bill's.
Therefore, Ben is traveling at a faster velocity.
### Summary
1. Bill's acceleration is [tex]\( 2.4 \, \text{m/s}^2 \)[/tex].
2. Ben's acceleration is approximately [tex]\( 0.8571 \, \text{m/s}^2 \)[/tex].
3. Ben is traveling at a faster velocity (21 m/s).
Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. Trust IDNLearn.com for all your queries. We appreciate your visit and hope to assist you again soon.