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Sagot :
To determine the total pounds of fruit Joanna bought, we add up the individual pounds of each fruit.
1. Apples: [tex]\(1 \frac{1}{2}\)[/tex] pounds
- This can be converted into an improper fraction: [tex]\(1 \frac{1}{2} = \frac{3}{2}\)[/tex] pounds.
2. Strawberries: [tex]\(\frac{3}{4}\)[/tex] of a pound.
3. Grapes: [tex]\(\frac{1}{2}\)[/tex] of a pound.
- This can also be written as [tex]\(\frac{2}{4}\)[/tex] to facilitate addition.
4. Oranges: [tex]\(1 \frac{3}{4}\)[/tex] pounds.
- This converts to an improper fraction: [tex]\(1 \frac{3}{4} = \frac{7}{4}\)[/tex] pounds.
5. Pears: [tex]\(1 \frac{1}{4}\)[/tex] pounds.
- This converts to an improper fraction: [tex]\(1 \frac{1}{4} = \frac{5}{4}\)[/tex] pounds.
Next, convert all amounts to either mixed fractions or improper fractions as necessary and sum them up:
[tex]\[ \begin{align*} \text{Apples} &: \frac{3}{2} = \frac{6}{4} \\ \text{Strawberries} &: \frac{3}{4} \\ \text{Grapes} &: \frac{2}{4} \\ \text{Oranges} &: \frac{7}{4} \\ \text{Pears} &: \frac{5}{4} \end{align*} \][/tex]
Combine all fractions over the common denominator 4:
[tex]\[ \frac{6}{4} + \frac{3}{4} + \frac{2}{4} + \frac{7}{4} + \frac{5}{4} = \frac{23}{4} \][/tex]
Convert back to a mixed number:
[tex]\[ \frac{23}{4} = 5 \frac{3}{4} \][/tex]
Thus, the total pounds of fruit Joanna bought is [tex]\(5 \frac{3}{4}\)[/tex] pounds.
So, the correct answer is:
B. [tex]\(5 \frac{3}{4}\)[/tex]
1. Apples: [tex]\(1 \frac{1}{2}\)[/tex] pounds
- This can be converted into an improper fraction: [tex]\(1 \frac{1}{2} = \frac{3}{2}\)[/tex] pounds.
2. Strawberries: [tex]\(\frac{3}{4}\)[/tex] of a pound.
3. Grapes: [tex]\(\frac{1}{2}\)[/tex] of a pound.
- This can also be written as [tex]\(\frac{2}{4}\)[/tex] to facilitate addition.
4. Oranges: [tex]\(1 \frac{3}{4}\)[/tex] pounds.
- This converts to an improper fraction: [tex]\(1 \frac{3}{4} = \frac{7}{4}\)[/tex] pounds.
5. Pears: [tex]\(1 \frac{1}{4}\)[/tex] pounds.
- This converts to an improper fraction: [tex]\(1 \frac{1}{4} = \frac{5}{4}\)[/tex] pounds.
Next, convert all amounts to either mixed fractions or improper fractions as necessary and sum them up:
[tex]\[ \begin{align*} \text{Apples} &: \frac{3}{2} = \frac{6}{4} \\ \text{Strawberries} &: \frac{3}{4} \\ \text{Grapes} &: \frac{2}{4} \\ \text{Oranges} &: \frac{7}{4} \\ \text{Pears} &: \frac{5}{4} \end{align*} \][/tex]
Combine all fractions over the common denominator 4:
[tex]\[ \frac{6}{4} + \frac{3}{4} + \frac{2}{4} + \frac{7}{4} + \frac{5}{4} = \frac{23}{4} \][/tex]
Convert back to a mixed number:
[tex]\[ \frac{23}{4} = 5 \frac{3}{4} \][/tex]
Thus, the total pounds of fruit Joanna bought is [tex]\(5 \frac{3}{4}\)[/tex] pounds.
So, the correct answer is:
B. [tex]\(5 \frac{3}{4}\)[/tex]
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