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The reaction between calcium carbonate [tex]$(CaCO_3)$[/tex] and hydrochloric acid [tex]$(HCl)$[/tex] produces calcium chloride [tex]$(CaCl_2)$[/tex], carbon dioxide [tex]$(CO_2)$[/tex], and water [tex]$(H_2O)$[/tex]. What happens when the concentration of hydrochloric acid [tex]$(HCl)$[/tex] molecules is doubled in this reaction?

[tex]$CaCO_3 + 2HCl \rightarrow CaCl_2 + CO_2 + H_2O$[/tex]

When the hydrochloric acid concentration doubles, the number of collisions between the reactants and the rate of the forward reaction [tex]$\square$[/tex].


Sagot :

When the concentration of hydrogen chloride (HCl) molecules is doubled in the reaction between calcium carbonate (CaCO₃) and HCl, several important changes occur at a molecular level:

1. Number of Collisions Between Reactants:
- According to collision theory, the rate of a chemical reaction depends on the number of effective collisions between reactant molecules.
- When the concentration of HCl is doubled, there are more HCl molecules present in a given volume.
- This leads to an increased frequency of collisions between HCl molecules and CaCO₃ molecules.

2. Rate of the Forward Reaction:
- An increase in the concentration of reactants generally leads to an increased rate of the forward reaction.
- With more frequent effective collisions (collisions that have the proper energy and orientation to lead to a reaction), the rate at which products are formed (CaCl₂, CO₂, and H₂O) will increase.

Thus, when the hydrogen chloride concentration is doubled:

When the hydrogen chloride concentration doubles, the number of collisions between the reactants increases and the rate of the forward reaction increases.

So, the correct and complete statement is:

When the hydrogen chloride concentration doubles, the number of collisions between the reactants increases and the rate of the forward reaction increases.
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