Connect with knowledgeable individuals and get your questions answered on IDNLearn.com. Explore a wide array of topics and find reliable answers from our experienced community members.

What is the concentration of [tex]\(OH^{-}\)[/tex] ions in a solution with a [tex]\(pOH\)[/tex] of 10.75?

A. [tex]\(3.162 \times 10^{-108} M\)[/tex]
B. [tex]\(1.778 \times 10^{-11} M\)[/tex]
C. [tex]\(1.075 \times 10^2 M\)[/tex]
D. [tex]\(5.623 \times 10^{10} M\)[/tex]


Sagot :

To determine the concentration of [tex]\( \text{OH}^- \)[/tex] ions in a solution given its [tex]\( \text{pOH} \)[/tex], we use the relationship between [tex]\( \text{pOH} \)[/tex] and the concentration of [tex]\( \text{OH}^- \)[/tex] ions, which is given by the formula:

[tex]\[ \left[ \text{OH}^- \right] = 10^{-\text{pOH}} \][/tex]

Here, we are provided with a [tex]\( \text{pOH} \)[/tex] value of 10.75. Let's go through the steps to find [tex]\( \left[ \text{OH}^- \right] \)[/tex]:

1. Identify the given [tex]\( \text{pOH} \)[/tex]:
[tex]\[ \text{pOH} = 10.75 \][/tex]

2. Substitute the [tex]\( \text{pOH} \)[/tex] value into the formula:
[tex]\[ \left[ \text{OH}^- \right] = 10^{-10.75} \][/tex]

3. Calculate the numerical value of [tex]\( 10^{-10.75} \)[/tex]:
Using a calculator or logarithmic tables, you will find that:
[tex]\[ 10^{-10.75} \approx 1.778 \times 10^{-11} \][/tex]

Therefore, the concentration of [tex]\( \text{OH}^- \)[/tex] ions in the solution is approximately [tex]\( 1.778 \times 10^{-11} \, \text{M} \)[/tex].

Among the given options, the correct answer is:

[tex]\[ 1.778 \times 10^{-11} \, \text{M} \][/tex]
Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. Your questions find clarity at IDNLearn.com. Thanks for stopping by, and come back for more dependable solutions.