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Simplify the following expression, if possible. Leave your answer in terms of [tex]$\sin(\theta)$[/tex] and [tex]$\cos(\theta)$[/tex].

[tex]$
\frac{\csc(\theta)}{\cot(\theta)} =
$[/tex]
[tex]$
\square
$[/tex]


Sagot :

To simplify the given expression [tex]\(\frac{\csc (\theta)}{\cot (\theta)}\)[/tex], let's start by recalling the definitions and relationships of the trigonometric functions involved:

1. [tex]\(\csc (\theta)\)[/tex] is the cosecant function, which is the reciprocal of the sine function. Therefore, we have:
[tex]\[ \csc (\theta) = \frac{1}{\sin (\theta)} \][/tex]

2. [tex]\(\cot (\theta)\)[/tex] is the cotangent function, which is the ratio of the cosine function to the sine function. Therefore, we have:
[tex]\[ \cot (\theta) = \frac{\cos (\theta)}{\sin (\theta)} \][/tex]

Now we substitute these definitions into the original expression:

[tex]\[ \frac{\csc (\theta)}{\cot (\theta)} = \frac{\frac{1}{\sin (\theta)}}{\frac{\cos (\theta)}{\sin (\theta)}} \][/tex]

We can simplify this complex fraction by multiplying the numerator by the reciprocal of the denominator. So we have:

[tex]\[ \frac{\csc (\theta)}{\cot (\theta)} = \frac{1}{\sin (\theta)} \times \frac{\sin (\theta)}{\cos (\theta)} \][/tex]

Here, the [tex]\(\sin (\theta)\)[/tex] terms in the numerator and the denominator cancel out each other:

[tex]\[ \frac{1}{\cos (\theta)} \][/tex]

Thus, the simplified form of the given expression is:

[tex]\[ \frac{\csc (\theta)}{\cot (\theta)} = \frac{1}{\cos (\theta)} \][/tex]