IDNLearn.com makes it easy to get reliable answers from experts and enthusiasts alike. Get accurate and detailed answers to your questions from our knowledgeable and dedicated community members.

Simplify the following expression, if possible. Leave your answer in terms of [tex]\(\sin(\theta)\)[/tex] and [tex]\(\cos(\theta)\)[/tex].

[tex]\[
(\sin(\theta) - \cos(\theta))^2 = \square
\][/tex]


Sagot :

To simplify the expression [tex]\((\sin(\theta) - \cos(\theta))^2\)[/tex], we will follow a step-by-step approach.

### Step 1: Expand using the Binomial Theorem

Recall that [tex]\((a - b)^2\)[/tex] can be expanded using the binomial theorem as:
[tex]\[ (a - b)^2 = a^2 - 2ab + b^2 \][/tex]

Here, [tex]\(a = \sin(\theta)\)[/tex] and [tex]\(b = \cos(\theta)\)[/tex]. Substituting these values into the binomial expansion, we get:
[tex]\[ (\sin(\theta) - \cos(\theta))^2 = \sin^2(\theta) - 2\sin(\theta)\cos(\theta) + \cos^2(\theta) \][/tex]

### Step 2: Use the Pythagorean Identity

There is a well-known trigonometric identity, called the Pythagorean identity, which states:
[tex]\[ \sin^2(\theta) + \cos^2(\theta) = 1 \][/tex]

Using this identity, we can substitute the sum [tex]\(\sin^2(\theta) + \cos^2(\theta)\)[/tex] with [tex]\(1\)[/tex].

### Step 3: Substitute and Simplify

Substitute the Pythagorean identity into our expanded expression:
[tex]\[ \sin^2(\theta) - 2\sin(\theta)\cos(\theta) + \cos^2(\theta) \][/tex]
[tex]\[ = (\sin^2(\theta) + \cos^2(\theta)) - 2\sin(\theta)\cos(\theta) \][/tex]
[tex]\[ = 1 - 2\sin(\theta)\cos(\theta) \][/tex]

### Final Simplified Expression

Therefore, the simplified form of the given expression is:
[tex]\[ (\sin(\theta) - \cos(\theta))^2 = 1 - 2\sin(\theta)\cos(\theta) \][/tex]

So the final answer is:
[tex]\[ 1 - 2\sin(\theta)\cos(\theta) \][/tex]
Thank you for participating in our discussion. We value every contribution. Keep sharing knowledge and helping others find the answers they need. Let's create a dynamic and informative learning environment together. Your questions find clarity at IDNLearn.com. Thanks for stopping by, and come back for more dependable solutions.