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Sagot :
Answer:
Step-by-step explanation: Sure, here are all of Phil's possible products:
Let's denote the cards as aa and bb, where aa and bb represent the values of the cards Phil picks.
Phil has 9 cards, so the possible values for each card range from 1 to 9.
The possible products are the result of multiplying each value of aa by each value of bb.
So, the possible products are:
1a,2a,3a,4a,5a,6a,7a,8a,9a1a,2a,3a,4a,5a,6a,7a,8a,9a
1b,2b,3b,4b,5b,6b,7b,8b,9b1b,2b,3b,4b,5b,6b,7b,8b,9b
Combining each possible value of aa with each possible value of bb, we get:
1×1,1×2,1×3,...,1×91×1,1×2,1×3,...,1×9
2×1,2×2,2×3,...,2×92×1,2×2,2×3,...,2×9
3×1,3×2,3×3,...,3×93×1,3×2,3×3,...,3×9
......
9×1,9×2,9×3,...,9×99×1,9×2,9×3,...,9×9
So, all of Phil's possible products are:
1,2,3,...,9,2,4,6,...,18,3,6,9,...,27,...,9,18,27,...,811,2,3,...,9,2,4,6,...,18,3,6,9,...,27,...,9,18,27,...,81
Hopefully this helps at least a little bit :)
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