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Final answer:
When crossing individuals with double heterozygous A+ and B+ blood types, the probability of getting a child with O+ blood type is 1/4.
Explanation:
Probability of offspring's blood type: When crossing individuals double heterozygous for A+ and B+ blood types, the Punnett square shows that the probability of getting a child with O+ blood type is 1/4. This is because out of the four possibilities (AA, Aa, BB, Bb), only the 'bb' genotype represents blood type O. Therefore, the chance of obtaining O+ blood type offspring is 1/4.
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