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What is the additive inverse of the complex number [tex]\( 9 - 4i \)[/tex]?

A. [tex]\(-9 - 4i\)[/tex]
B. [tex]\(-9 + 4i\)[/tex]
C. [tex]\(9 - 4i\)[/tex]
D. [tex]\(9 + 4i\)[/tex]

Sagot :

GinnyAnsweridn
To find the additive inverse of a complex number, we need to negate both the real part and the imaginary part of the complex number.

Given the complex number [tex]\(9 - 4i\)[/tex]:

1. The real part of the number is [tex]\(9\)[/tex].
2. The imaginary part of the number is [tex]\(-4i\)[/tex].

To find the additive inverse, we negate both parts:

1. Negating the real part: [tex]\(-9\)[/tex].
2. Negating the imaginary part: [tex]\(+4i\)[/tex].

Therefore, the additive inverse of the complex number [tex]\(9 - 4i\)[/tex] is [tex]\(-9 + 4i\)[/tex].

So the correct answer is:
[tex]\[ -9 + 4i \][/tex]
Ariannaleijaaidn
the answer to your question is b. -9+4i.
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