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What is the volume of a cylinder with a height of 16.9 in and a base diameter of 9.6 in, to the nearest tenth of a cubic inch?

Sagot :

To find the volume of a cylinder, we can use the formula for the volume [tex]\( V \)[/tex] of a cylinder:

[tex]\[ V = \pi r^2 h \][/tex]

where:
- [tex]\( \pi \)[/tex] (Pi) is a constant approximately equal to 3.14159,
- [tex]\( r \)[/tex] is the radius of the base of the cylinder, and
- [tex]\( h \)[/tex] is the height of the cylinder.

Given the following dimensions:
- Height [tex]\( h = 16.9 \)[/tex] inches,
- Diameter of the base [tex]\( d = 9.6 \)[/tex] inches.

### Step-by-Step Solution:

1. Calculate the radius [tex]\( r \)[/tex]:
The radius [tex]\( r \)[/tex] is half of the diameter.
[tex]\[ r = \frac{d}{2} = \frac{9.6}{2} = 4.8 \, \text{inches} \][/tex]

2. Apply the volume formula for the cylinder:
[tex]\[ V = \pi r^2 h \][/tex]

Plugging in the values we have:
[tex]\[ V = \pi (4.8)^2 (16.9) \][/tex]

3. Square the radius [tex]\( r \)[/tex]:
[tex]\[ 4.8^2 = 23.04 \][/tex]

4. Multiply by height [tex]\( h \)[/tex]:
[tex]\[ 23.04 \times 16.9 = 389.376 \][/tex]

5. Multiply by [tex]\( \pi \)[/tex]:
[tex]\[ V = \pi \times 389.376 \approx 1223.2607810841791 \, \text{cubic inches} \][/tex]

6. Round to the nearest tenth:
The nearest tenth of [tex]\( 1223.2607810841791 \)[/tex] is [tex]\( 1223.3 \)[/tex].

### Final Answer:
The volume of the cylinder, rounded to the nearest tenth of a cubic inch, is [tex]\( 1223.3 \, \text{cubic inches} \)[/tex].