Get the answers you've been looking for with the help of IDNLearn.com's expert community. Ask your questions and receive reliable and comprehensive answers from our dedicated community of professionals.

Find the volume of a right circular cone with a height of 10.6 m and a base diameter of 18.5 m. Round your answer to the nearest tenth of a cubic meter.

Answer: _____ m³


Sagot :

Sure, let's break down the solution step-by-step.

1. Identify the Given Values:
- Height ([tex]\( h \)[/tex]) of the cone = 10.6 meters
- Diameter ([tex]\( d \)[/tex]) of the base of the cone = 18.5 meters

2. Calculate the Radius of the Base:
The radius ([tex]\( r \)[/tex]) is half of the diameter.
[tex]\[ r = \frac{d}{2} = \frac{18.5}{2} = 9.25 \text{ meters} \][/tex]

3. Formula for the Volume of a Right Circular Cone:
The formula to find the volume ([tex]\( V \)[/tex]) of a right circular cone is:
[tex]\[ V = \frac{1}{3} \pi r^2 h \][/tex]

4. Plug in the Known Values into the Formula:
[tex]\[ V = \frac{1}{3} \pi (9.25)^2 (10.6) \][/tex]
- First, calculate [tex]\( r^2 \)[/tex]:
[tex]\[ r^2 = 9.25^2 = 85.5625 \][/tex]
- Now, multiply by the height ([tex]\( h \)[/tex]):
[tex]\[ 85.5625 \times 10.6 = 906.9625 \][/tex]
- Then, multiply by [tex]\( \frac{1}{3} \pi \)[/tex]:
[tex]\[ V = \frac{1}{3} \pi \times 906.9625 \][/tex]

5. Compute the Volume:
Using the value of [tex]\( \pi \approx 3.141592653589793 \)[/tex],
[tex]\[ V \approx \frac{1}{3} \times 3.141592653589793 \times 906.9625 \approx 949.7689090271442 \][/tex]

6. Round the Volume to the Nearest Tenth:
The computed volume is 949.7689090271442 cubic meters. When rounding to the nearest tenth, the result is:
[tex]\[ V \approx 949.8 \text{ cubic meters} \][/tex]

Therefore, the volume of the right circular cone, rounded to the nearest tenth, is [tex]\( 949.8 \)[/tex] cubic meters.