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Which conversion factor should be used to solve the following:

"How many moles are in 28 grams of CO₂?"

A. 1 mol = 6.02 x 10²³ atoms
B. 1 mol = 44.01 g
C. 1 mol = 22.4 L
D. More than one


Sagot :

To determine how many moles are in 28 grams of CO₂, you need to use the correct conversion factor. The given options include several different conversion factors:

1. [tex]\( 1 \text{ mol} = 6.02 \times 10^{23} \)[/tex] atoms
2. [tex]\( 1 \text{ mol} = 44.01 \text{ g} \)[/tex]
3. [tex]\( 1 \text{ mol} = 22.4 \text{ L} \)[/tex]

We know that the molar mass of CO₂ (carbon dioxide) is 44.01 grams per mole. This means that 1 mole of CO₂ weighs 44.01 grams.

To find out how many moles are in 28 grams of CO₂, we can use the conversion factor [tex]\( 1 \text{ mol} = 44.01 \text{ g} \)[/tex].

First, we'll set up the conversion:

[tex]\[ \text{Number of moles} = \frac{\text{Given mass of CO₂}}{\text{Molar mass of CO₂}} \][/tex]

Substitute the given values into the formula:

[tex]\[ \text{Number of moles} = \frac{28 \text{ g}}{44.01 \text{ g/mol}} \][/tex]

This calculation yields the number of moles:

[tex]\[ \text{Number of moles} \approx 0.6362 \][/tex]

Thus, the correct conversion factor to use in this context is [tex]\( 1 \text{ mol} = 44.01 \text{ g} \)[/tex].