IDNLearn.com connects you with a community of knowledgeable individuals ready to help. Our Q&A platform is designed to provide quick and accurate answers to any questions you may have.
Sagot :
To solve the equation [tex]\( m^3 = 8 \)[/tex], we need to determine the values of [tex]\( m \)[/tex] such that when [tex]\( m \)[/tex] is cubed, the result is 8. Let's go through the steps to find these solutions:
1. Identify the cube root of 8:
By definition, the cube root of a number [tex]\( n \)[/tex] is a value [tex]\( m \)[/tex] such that when raised to the power of 3, it equals [tex]\( n \)[/tex]. Thus, for [tex]\( m^3 = 8 \)[/tex], we need to find the value of [tex]\( m \)[/tex] such that:
[tex]\[ m = \sqrt[3]{8} \][/tex]
2. Solving the equation:
- Calculate [tex]\( \sqrt[3]{8} \)[/tex]:
We know that 8 is equal to [tex]\( 2^3 \)[/tex]. Consequently:
[tex]\[ \sqrt[3]{8} = \sqrt[3]{2^3} = 2 \][/tex]
Hence, [tex]\( m = 2 \)[/tex] is a solution.
- Confirm that [tex]\( m = 2 \)[/tex] satisfies the original equation:
[tex]\[ (2)^3 = 2 \times 2 \times 2 = 8 \][/tex]
This confirms that [tex]\( m = 2 \)[/tex] is indeed a solution.
3. Evaluate the other potential solutions given in the options:
- Option A: 2
As shown above, [tex]\( 2 \)[/tex] is indeed a solution because [tex]\( 2^3 = 8 \)[/tex].
- Option B: 4
[tex]\[ 4^3 = 4 \times 4 \times 4 = 64 \][/tex]
Hence, [tex]\( 4 \)[/tex] is not a solution.
- Option C: 243
[tex]\[ 243^3 = 243 \times 243 \times 243 \][/tex]
Clearly, this value is much larger than 8, so [tex]\( 243 \)[/tex] is not a solution.
- Option D: [tex]\( \sqrt[3]{8} \)[/tex]
By the calculation above, we have:
[tex]\[ \sqrt[3]{8} = 2 \][/tex]
So, [tex]\( \sqrt[3]{8} \)[/tex] is indeed a solution.
- Option E: [tex]\( \sqrt{8} \)[/tex]
[tex]\[ \sqrt{8} = \sqrt{4 \times 2} = \sqrt{4} \times \sqrt{2} = 2\sqrt{2} \][/tex]
And,
[tex]\[ (2\sqrt{2})^3 = 8 \sqrt{2^3} = 8\sqrt{8} \][/tex]
Hence, [tex]\( \sqrt{8} \)[/tex] is not a solution.
Based on the detailed evaluation, the two values that are solutions to the equation [tex]\( m^3 = 8 \)[/tex] are:
- Option A: 2
- Option D: [tex]\( \sqrt[3]{8} \)[/tex]
Therefore, the correct choices are A (2) and D ([tex]\(\sqrt[3]{8}\)[/tex]).
1. Identify the cube root of 8:
By definition, the cube root of a number [tex]\( n \)[/tex] is a value [tex]\( m \)[/tex] such that when raised to the power of 3, it equals [tex]\( n \)[/tex]. Thus, for [tex]\( m^3 = 8 \)[/tex], we need to find the value of [tex]\( m \)[/tex] such that:
[tex]\[ m = \sqrt[3]{8} \][/tex]
2. Solving the equation:
- Calculate [tex]\( \sqrt[3]{8} \)[/tex]:
We know that 8 is equal to [tex]\( 2^3 \)[/tex]. Consequently:
[tex]\[ \sqrt[3]{8} = \sqrt[3]{2^3} = 2 \][/tex]
Hence, [tex]\( m = 2 \)[/tex] is a solution.
- Confirm that [tex]\( m = 2 \)[/tex] satisfies the original equation:
[tex]\[ (2)^3 = 2 \times 2 \times 2 = 8 \][/tex]
This confirms that [tex]\( m = 2 \)[/tex] is indeed a solution.
3. Evaluate the other potential solutions given in the options:
- Option A: 2
As shown above, [tex]\( 2 \)[/tex] is indeed a solution because [tex]\( 2^3 = 8 \)[/tex].
- Option B: 4
[tex]\[ 4^3 = 4 \times 4 \times 4 = 64 \][/tex]
Hence, [tex]\( 4 \)[/tex] is not a solution.
- Option C: 243
[tex]\[ 243^3 = 243 \times 243 \times 243 \][/tex]
Clearly, this value is much larger than 8, so [tex]\( 243 \)[/tex] is not a solution.
- Option D: [tex]\( \sqrt[3]{8} \)[/tex]
By the calculation above, we have:
[tex]\[ \sqrt[3]{8} = 2 \][/tex]
So, [tex]\( \sqrt[3]{8} \)[/tex] is indeed a solution.
- Option E: [tex]\( \sqrt{8} \)[/tex]
[tex]\[ \sqrt{8} = \sqrt{4 \times 2} = \sqrt{4} \times \sqrt{2} = 2\sqrt{2} \][/tex]
And,
[tex]\[ (2\sqrt{2})^3 = 8 \sqrt{2^3} = 8\sqrt{8} \][/tex]
Hence, [tex]\( \sqrt{8} \)[/tex] is not a solution.
Based on the detailed evaluation, the two values that are solutions to the equation [tex]\( m^3 = 8 \)[/tex] are:
- Option A: 2
- Option D: [tex]\( \sqrt[3]{8} \)[/tex]
Therefore, the correct choices are A (2) and D ([tex]\(\sqrt[3]{8}\)[/tex]).
Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! Your questions are important to us at IDNLearn.com. Thanks for stopping by, and come back for more reliable solutions.