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Which equation is related to [tex]\(\sqrt{x+10} - 1 = x\)[/tex]?

A. [tex]\(x + 10 = x^2 + x + 1\)[/tex]
B. [tex]\(x + 10 = x^2 + 2x + 1\)[/tex]
C. [tex]\(x + 10 = x^2 + 1\)[/tex]
D. [tex]\(x + 10 = x^2 - 1\)[/tex]


Sagot :

Let's solve the equation [tex]\(\sqrt{x + 10} - 1 = x\)[/tex] step-by-step.

1. Isolate the square root term:
Start by adding 1 to both sides of the equation:
[tex]\[ \sqrt{x + 10} = x + 1 \][/tex]

2. Square both sides:
To eliminate the square root, square both sides of the equation:
[tex]\[ (\sqrt{x + 10})^2 = (x + 1)^2 \][/tex]
This simplifies to:
[tex]\[ x + 10 = (x + 1)^2 \][/tex]

3. Expand the right side:
Expand [tex]\((x + 1)^2\)[/tex]:
[tex]\[ x + 10 = x^2 + 2x + 1 \][/tex]

4. Rearrange the equation:
Finally, move all terms to one side to form a standard quadratic equation:
[tex]\[ x + 10 = x^2 + 2x + 1 \][/tex]
Subtract [tex]\(x + 10\)[/tex] from both sides:
[tex]\[ 0 = x^2 + x - 9 \][/tex]

Therefore, the equation [tex]\(\sqrt{x + 10} - 1 = x\)[/tex] simplifies to [tex]\(x + 10 = x^2 + 2x + 1\)[/tex].

Thus, the second equation, [tex]\(x+10 = x^2 + 2x + 1\)[/tex], is the one that matches the transformed form of [tex]\(\sqrt{x + 10} - 1 = x\)[/tex].
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