Answered

Get expert insights and community-driven knowledge on IDNLearn.com. Our experts provide timely, comprehensive responses to ensure you have the information you need.

In the standard (x, y) coordinate plane, point A has coordinates (-4, -5). Point A is translated 4 units to the right and 5 units down. What are the coordinates of the image [tex]\( A' \)[/tex]?

A. (-9, -9)
B. (-8, -10)
C. (-4, -10)
D. (0, -10)
E. (8, 10)

Sagot :

GinnyAnsweridn
To solve this problem, let's go through it step by step.

1. Initial Coordinates of Point A:
Point [tex]\( A \)[/tex] has coordinates [tex]\((-4, -5)\)[/tex].

2. Translation Information:
- We need to translate the point 4 units to the right. Moving right means we add 4 to the x-coordinate.
- We also need to translate the point 5 units down. Moving down means we subtract 5 from the y-coordinate.

3. Calculate New Coordinates:
- For the x-coordinate: [tex]\( -4 + 4 \)[/tex]
- For the y-coordinate: [tex]\( -5 - 5 \)[/tex]

Let's compute these:
- New x-coordinate: [tex]\(-4 + 4 = 0\)[/tex]
- New y-coordinate: [tex]\(-5 - 5 = -10\)[/tex]

4. New Coordinates of Point [tex]\( A^{\prime} \)[/tex]:
After the translation, the new coordinates [tex]\( A^{\prime} \)[/tex] are [tex]\((0, -10)\)[/tex].

Thus, the coordinates of [tex]\( A^{\prime} \)[/tex] are [tex]\((0, -10)\)[/tex], which corresponds to option D.

Answer: [tex]\( D. (0, -10) \)[/tex]
Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. IDNLearn.com is dedicated to providing accurate answers. Thank you for visiting, and see you next time for more solutions.