IDNLearn.com: Your one-stop destination for finding reliable answers. Discover in-depth answers from knowledgeable professionals, providing you with the information you need.
Sagot :
To solve the problem of balancing the chemical equation [tex]\( \text{Na}_{(s)} + \text{H}_2\text{O} \rightarrow \text{NaOH} + \text{H}_2 \)[/tex], follow these steps:
1. Identify the Reactants and Products:
- Reactants: Sodium (Na) and Water ([tex]\(\text{H}_2\text{O}\)[/tex])
- Products: Sodium Hydroxide ([tex]\(\text{NaOH}\)[/tex]) and Hydrogen Gas ([tex]\(\text{H}_2\)[/tex])
2. Write Down the Unbalanced Equation:
[tex]\[ \text{Na} + \text{H}_2\text{O} \rightarrow \text{NaOH} + \text{H}_2 \][/tex]
3. Count the Number of Atoms of Each Element on Both Sides:
- Left side (Reactants):
- Na: 1
- H: 2 (from [tex]\(\text{H}_2\text{O}\)[/tex])
- O: 1 (from [tex]\(\text{H}_2\text{O}\)[/tex])
- Right side (Products):
- Na: 1 (from [tex]\(\text{NaOH}\)[/tex])
- H: 3 (1 from [tex]\(\text{NaOH}\)[/tex] and 2 from [tex]\(\text{H}_2\)[/tex])
- O: 1 (from [tex]\(\text{NaOH}\)[/tex])
4. Adjust the Coefficients to Balance Each Element:
- Sodium (Na) atoms are already balanced (1 on each side).
- Next, balance the Hydrogen (H) atoms.
- There are 2 H atoms on the reactants side (from [tex]\(\text{H}_2\text{O}\)[/tex]) and 3 on the products side (1 from [tex]\(\text{NaOH}\)[/tex] and 2 from [tex]\(\text{H}_2\)[/tex]).
- To balance H atoms, place a coefficient of 2 before both [tex]\(\text{H}_2\text{O}\)[/tex] and [tex]\(\text{NaOH}\)[/tex]:
[tex]\[ \text{Na} + 2 \text{H}_2\text{O} \rightarrow 2 \text{NaOH} + \text{H}_2 \][/tex]
- Finally, balance the Sodium (Na) atoms:
- There is now 1 Na atom on the reactants side, but we need 2 to balance the 2 Na atoms present in [tex]\(\text{NaOH}\)[/tex].
- Place a coefficient of 2 before Na:
[tex]\[ 2 \text{Na} + 2 \text{H}_2\text{O} \rightarrow 2 \text{NaOH} + \text{H}_2 \][/tex]
5. Verify the Balance of Each Element:
- Na: 2 atoms on reactants side and 2 atoms on the products side.
- H: 4 atoms on reactants side (from 2 [tex]\(\text{H}_2\text{O}\)[/tex]) and 4 atoms on the products side (2 from 2 [tex]\(\text{NaOH}\)[/tex] and 2 from [tex]\(\text{H}_2\)[/tex]).
- O: 2 atoms on reactants side (from 2 [tex]\(\text{H}_2\text{O}\)[/tex]) and 2 atoms on the products side (from 2 [tex]\(\text{NaOH}\)[/tex]).
6. Write the Final Balanced Chemical Equation:
[tex]\[ \boxed{2 \text{Na} + 2 \text{H}_2\text{O} \rightarrow 2 \text{NaOH} + \text{H}_2} \][/tex]
1. Identify the Reactants and Products:
- Reactants: Sodium (Na) and Water ([tex]\(\text{H}_2\text{O}\)[/tex])
- Products: Sodium Hydroxide ([tex]\(\text{NaOH}\)[/tex]) and Hydrogen Gas ([tex]\(\text{H}_2\)[/tex])
2. Write Down the Unbalanced Equation:
[tex]\[ \text{Na} + \text{H}_2\text{O} \rightarrow \text{NaOH} + \text{H}_2 \][/tex]
3. Count the Number of Atoms of Each Element on Both Sides:
- Left side (Reactants):
- Na: 1
- H: 2 (from [tex]\(\text{H}_2\text{O}\)[/tex])
- O: 1 (from [tex]\(\text{H}_2\text{O}\)[/tex])
- Right side (Products):
- Na: 1 (from [tex]\(\text{NaOH}\)[/tex])
- H: 3 (1 from [tex]\(\text{NaOH}\)[/tex] and 2 from [tex]\(\text{H}_2\)[/tex])
- O: 1 (from [tex]\(\text{NaOH}\)[/tex])
4. Adjust the Coefficients to Balance Each Element:
- Sodium (Na) atoms are already balanced (1 on each side).
- Next, balance the Hydrogen (H) atoms.
- There are 2 H atoms on the reactants side (from [tex]\(\text{H}_2\text{O}\)[/tex]) and 3 on the products side (1 from [tex]\(\text{NaOH}\)[/tex] and 2 from [tex]\(\text{H}_2\)[/tex]).
- To balance H atoms, place a coefficient of 2 before both [tex]\(\text{H}_2\text{O}\)[/tex] and [tex]\(\text{NaOH}\)[/tex]:
[tex]\[ \text{Na} + 2 \text{H}_2\text{O} \rightarrow 2 \text{NaOH} + \text{H}_2 \][/tex]
- Finally, balance the Sodium (Na) atoms:
- There is now 1 Na atom on the reactants side, but we need 2 to balance the 2 Na atoms present in [tex]\(\text{NaOH}\)[/tex].
- Place a coefficient of 2 before Na:
[tex]\[ 2 \text{Na} + 2 \text{H}_2\text{O} \rightarrow 2 \text{NaOH} + \text{H}_2 \][/tex]
5. Verify the Balance of Each Element:
- Na: 2 atoms on reactants side and 2 atoms on the products side.
- H: 4 atoms on reactants side (from 2 [tex]\(\text{H}_2\text{O}\)[/tex]) and 4 atoms on the products side (2 from 2 [tex]\(\text{NaOH}\)[/tex] and 2 from [tex]\(\text{H}_2\)[/tex]).
- O: 2 atoms on reactants side (from 2 [tex]\(\text{H}_2\text{O}\)[/tex]) and 2 atoms on the products side (from 2 [tex]\(\text{NaOH}\)[/tex]).
6. Write the Final Balanced Chemical Equation:
[tex]\[ \boxed{2 \text{Na} + 2 \text{H}_2\text{O} \rightarrow 2 \text{NaOH} + \text{H}_2} \][/tex]
We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Your questions find clarity at IDNLearn.com. Thanks for stopping by, and come back for more dependable solutions.
