IDNLearn.com: Your one-stop destination for reliable answers to diverse questions. Ask any question and receive comprehensive, well-informed responses from our dedicated team of experts.
Sagot :
To find the standard deviation of the given sample of red blood cell counts, we'll follow a step-by-step calculation process:
1. List the data: The counts are [tex]\(49, 55, 52, 54, 50\)[/tex].
2. Calculate the mean ([tex]\(\overline{x}\)[/tex]):
[tex]\[ \overline{x} = \frac{\sum_{i=1}^{n} x_i}{n} \][/tex]
Where [tex]\( n \)[/tex] is the number of data points.
[tex]\[ \overline{x} = \frac{49 + 55 + 52 + 54 + 50}{5} = \frac{260}{5} = 52.0 \][/tex]
3. Calculate each data point's deviation from the mean and square the result:
[tex]\[ (49 - 52)^2 = (-3)^2 = 9 \][/tex]
[tex]\[ (55 - 52)^2 = 3^2 = 9 \][/tex]
[tex]\[ (52 - 52)^2 = 0^2 = 0 \][/tex]
[tex]\[ (54 - 52)^2 = 2^2 = 4 \][/tex]
[tex]\[ (50 - 52)^2 = (-2)^2 = 4 \][/tex]
4. Sum these squared deviations:
[tex]\[ 9 + 9 + 0 + 4 + 4 = 26 \][/tex]
5. Calculate the variance (s^2) using the sample variance formula:
[tex]\[ s^2 = \frac{\sum_{i=1}^{n} (x_i - \overline{x})^2}{n-1} \][/tex]
[tex]\[ s^2 = \frac{26}{4} = 6.5 \][/tex]
6. Calculate the standard deviation (s):
The standard deviation is the square root of the variance.
[tex]\[ s = \sqrt{s^2} = \sqrt{6.5} \approx 2.5495097567963922 \][/tex]
7. Round the standard deviation to two decimal places:
[tex]\[ s \approx 2.55 \][/tex]
Therefore, the standard deviation of this sample of red blood cell counts is approximately [tex]\( 2.55 \)[/tex] (rounded to two decimal places).
1. List the data: The counts are [tex]\(49, 55, 52, 54, 50\)[/tex].
2. Calculate the mean ([tex]\(\overline{x}\)[/tex]):
[tex]\[ \overline{x} = \frac{\sum_{i=1}^{n} x_i}{n} \][/tex]
Where [tex]\( n \)[/tex] is the number of data points.
[tex]\[ \overline{x} = \frac{49 + 55 + 52 + 54 + 50}{5} = \frac{260}{5} = 52.0 \][/tex]
3. Calculate each data point's deviation from the mean and square the result:
[tex]\[ (49 - 52)^2 = (-3)^2 = 9 \][/tex]
[tex]\[ (55 - 52)^2 = 3^2 = 9 \][/tex]
[tex]\[ (52 - 52)^2 = 0^2 = 0 \][/tex]
[tex]\[ (54 - 52)^2 = 2^2 = 4 \][/tex]
[tex]\[ (50 - 52)^2 = (-2)^2 = 4 \][/tex]
4. Sum these squared deviations:
[tex]\[ 9 + 9 + 0 + 4 + 4 = 26 \][/tex]
5. Calculate the variance (s^2) using the sample variance formula:
[tex]\[ s^2 = \frac{\sum_{i=1}^{n} (x_i - \overline{x})^2}{n-1} \][/tex]
[tex]\[ s^2 = \frac{26}{4} = 6.5 \][/tex]
6. Calculate the standard deviation (s):
The standard deviation is the square root of the variance.
[tex]\[ s = \sqrt{s^2} = \sqrt{6.5} \approx 2.5495097567963922 \][/tex]
7. Round the standard deviation to two decimal places:
[tex]\[ s \approx 2.55 \][/tex]
Therefore, the standard deviation of this sample of red blood cell counts is approximately [tex]\( 2.55 \)[/tex] (rounded to two decimal places).
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com provides the best answers to your questions. Thank you for visiting, and come back soon for more helpful information.