Get personalized answers to your unique questions on IDNLearn.com. Join our interactive Q&A platform to receive prompt and accurate responses from experienced professionals in various fields.
Sagot :
To determine whether being from California and preferring brand B are independent events, we need to check if the probability of being from California and preferring brand B equals the product of the individual probabilities of being from California and preferring brand B. Let us break it down step by step:
1. Calculate [tex]\( P(\text{California}) \)[/tex]:
- The total number of people surveyed is 275.
- The number of people from California is 150.
- Therefore, [tex]\( P(\text{California}) = \frac{150}{275} \approx 0.545 \)[/tex].
2. Calculate [tex]\( P(\text{Brand B}) \)[/tex]:
- The total number of people who prefer Brand B is 99.
- Therefore, [tex]\( P(\text{Brand B}) = \frac{99}{275} \approx 0.36 \)[/tex].
3. Calculate [tex]\( P(\text{California and Brand B}) \)[/tex]:
- The number of people from California who prefer Brand B is 54.
- Therefore, [tex]\( P(\text{California and Brand B}) = \frac{54}{275} \approx 0.196 \)[/tex].
4. Calculate [tex]\( P(\text{California} | \text{Brand B}) \)[/tex]:
- The number of people who prefer Brand B is 99.
- The number of those who are from California and prefer Brand B is 54.
- Therefore, [tex]\( P(\text{California} | \text{Brand B}) = \frac{54}{99} \approx 0.545 \)[/tex].
5. Check for Independence:
- Events [tex]\( A \)[/tex] and [tex]\( B \)[/tex] are independent if and only if [tex]\( P(A \text{ and } B) = P(A) \cdot P(B) \)[/tex].
- Calculate [tex]\( P(\text{California}) \times P(\text{Brand B}) \)[/tex]:
[tex]\[ P(\text{California}) \times P(\text{Brand B}) = 0.545 \times 0.36 \approx 0.196. \][/tex]
- Compare this with [tex]\( P(\text{California and Brand B}) \)[/tex]:
[tex]\[ P(\text{California and Brand B}) \approx 0.196. \][/tex]
- Since [tex]\( P(\text{California}) \times P(\text{Brand B}) \approx P(\text{California and Brand B}) \)[/tex], the events are independent.
Therefore, the correct option is:
A. Yes, they are independent because [tex]\( P(\text{California}) \approx 0.55 \)[/tex] and [tex]\( P(\text{California} | \text{Brand B}) \approx 0.55 \)[/tex].
1. Calculate [tex]\( P(\text{California}) \)[/tex]:
- The total number of people surveyed is 275.
- The number of people from California is 150.
- Therefore, [tex]\( P(\text{California}) = \frac{150}{275} \approx 0.545 \)[/tex].
2. Calculate [tex]\( P(\text{Brand B}) \)[/tex]:
- The total number of people who prefer Brand B is 99.
- Therefore, [tex]\( P(\text{Brand B}) = \frac{99}{275} \approx 0.36 \)[/tex].
3. Calculate [tex]\( P(\text{California and Brand B}) \)[/tex]:
- The number of people from California who prefer Brand B is 54.
- Therefore, [tex]\( P(\text{California and Brand B}) = \frac{54}{275} \approx 0.196 \)[/tex].
4. Calculate [tex]\( P(\text{California} | \text{Brand B}) \)[/tex]:
- The number of people who prefer Brand B is 99.
- The number of those who are from California and prefer Brand B is 54.
- Therefore, [tex]\( P(\text{California} | \text{Brand B}) = \frac{54}{99} \approx 0.545 \)[/tex].
5. Check for Independence:
- Events [tex]\( A \)[/tex] and [tex]\( B \)[/tex] are independent if and only if [tex]\( P(A \text{ and } B) = P(A) \cdot P(B) \)[/tex].
- Calculate [tex]\( P(\text{California}) \times P(\text{Brand B}) \)[/tex]:
[tex]\[ P(\text{California}) \times P(\text{Brand B}) = 0.545 \times 0.36 \approx 0.196. \][/tex]
- Compare this with [tex]\( P(\text{California and Brand B}) \)[/tex]:
[tex]\[ P(\text{California and Brand B}) \approx 0.196. \][/tex]
- Since [tex]\( P(\text{California}) \times P(\text{Brand B}) \approx P(\text{California and Brand B}) \)[/tex], the events are independent.
Therefore, the correct option is:
A. Yes, they are independent because [tex]\( P(\text{California}) \approx 0.55 \)[/tex] and [tex]\( P(\text{California} | \text{Brand B}) \approx 0.55 \)[/tex].
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Find reliable answers at IDNLearn.com. Thanks for stopping by, and come back for more trustworthy solutions.