Discover a wealth of information and get your questions answered on IDNLearn.com. Our platform offers reliable and detailed answers, ensuring you have the information you need.
Sagot :
Certainly! Let's carefully examine each reaction to predict whether it will occur based on the activity series of halogens: [tex]\( F_2 > Cl_2 > Br_2 > I_2 \)[/tex].
### Reaction 1: [tex]\( Cl_2 + 2 RbI \rightarrow 2 RbCl + I_2 \)[/tex]
1. Identify Reactants and Products:
- Reactants: [tex]\( Cl_2 \)[/tex] and [tex]\( RbI \)[/tex]
- Products: [tex]\( RbCl \)[/tex] and [tex]\( I_2 \)[/tex]
2. Understand the Activity Series:
- Chlorine ([tex]\( Cl_2 \)[/tex]) and iodine ([tex]\( I_2 \)[/tex]) are both halogens, and they are in the activity series provided.
- The activity series tells us the relative reactivity of the halogens: [tex]\( F_2 > Cl_2 > Br_2 > I_2 \)[/tex].
3. Compare Reactivities (Activity Series):
- According to the activity series, chlorine ([tex]\( Cl_2 \)[/tex]) is more reactive than iodine ([tex]\( I_2 \)[/tex]).
4. Predict the Reaction:
- Since [tex]\( Cl_2 \)[/tex] is more reactive than [tex]\( I_2 \)[/tex], [tex]\( Cl_2 \)[/tex] will displace [tex]\( I \)[/tex] in [tex]\( RbI \)[/tex], forming [tex]\( RbCl \)[/tex] and releasing [tex]\( I_2 \)[/tex].
Conclusion for Reaction 1:
- The reaction [tex]\( Cl_2 + 2 RbI \rightarrow 2 RbCl + I_2 \)[/tex] will take place.
### Reaction 2: [tex]\( I_2 + NiBr_2 \rightarrow NiI_2 + Br_2 \)[/tex]
1. Identify Reactants and Products:
- Reactants: [tex]\( I_2 \)[/tex] and [tex]\( NiBr_2 \)[/tex]
- Products: [tex]\( NiI_2 \)[/tex] and [tex]\( Br_2 \)[/tex]
2. Understand the Activity Series:
- Iodine ([tex]\( I_2 \)[/tex]) and bromine ([tex]\( Br_2 \)[/tex]) are both halogens, and they are in the activity series provided.
- The activity series tells us the relative reactivity of the halogens: [tex]\( F_2 > Cl_2 > Br_2 > I_2 \)[/tex].
3. Compare Reactivities (Activity Series):
- According to the activity series, iodine ([tex]\( I_2 \)[/tex]) is less reactive than bromine ([tex]\( Br_2 \)[/tex]).
4. Predict the Reaction:
- Since [tex]\( I_2 \)[/tex] is less reactive than [tex]\( Br_2 \)[/tex], [tex]\( I_2 \)[/tex] cannot displace [tex]\( Br \)[/tex] in [tex]\( NiBr_2 \)[/tex], so the reaction will not proceed.
Conclusion for Reaction 2:
- The reaction [tex]\( I_2 + NiBr_2 \rightarrow NiI_2 + Br_2 \)[/tex] will not take place.
### Final Prediction:
Based on the analysis:
- Reaction 1 ([tex]\( Cl_2 + 2 RbI \rightarrow 2 RbCl + I_2 \)[/tex]) will occur, indicated by 1.
- Reaction 2 ([tex]\( I_2 + NiBr_2 \rightarrow NiI_2 + Br_2 \)[/tex]) will not occur, indicated by 0.
Therefore, the expected results are:
[tex]\[ (1, 0) \][/tex]
### Reaction 1: [tex]\( Cl_2 + 2 RbI \rightarrow 2 RbCl + I_2 \)[/tex]
1. Identify Reactants and Products:
- Reactants: [tex]\( Cl_2 \)[/tex] and [tex]\( RbI \)[/tex]
- Products: [tex]\( RbCl \)[/tex] and [tex]\( I_2 \)[/tex]
2. Understand the Activity Series:
- Chlorine ([tex]\( Cl_2 \)[/tex]) and iodine ([tex]\( I_2 \)[/tex]) are both halogens, and they are in the activity series provided.
- The activity series tells us the relative reactivity of the halogens: [tex]\( F_2 > Cl_2 > Br_2 > I_2 \)[/tex].
3. Compare Reactivities (Activity Series):
- According to the activity series, chlorine ([tex]\( Cl_2 \)[/tex]) is more reactive than iodine ([tex]\( I_2 \)[/tex]).
4. Predict the Reaction:
- Since [tex]\( Cl_2 \)[/tex] is more reactive than [tex]\( I_2 \)[/tex], [tex]\( Cl_2 \)[/tex] will displace [tex]\( I \)[/tex] in [tex]\( RbI \)[/tex], forming [tex]\( RbCl \)[/tex] and releasing [tex]\( I_2 \)[/tex].
Conclusion for Reaction 1:
- The reaction [tex]\( Cl_2 + 2 RbI \rightarrow 2 RbCl + I_2 \)[/tex] will take place.
### Reaction 2: [tex]\( I_2 + NiBr_2 \rightarrow NiI_2 + Br_2 \)[/tex]
1. Identify Reactants and Products:
- Reactants: [tex]\( I_2 \)[/tex] and [tex]\( NiBr_2 \)[/tex]
- Products: [tex]\( NiI_2 \)[/tex] and [tex]\( Br_2 \)[/tex]
2. Understand the Activity Series:
- Iodine ([tex]\( I_2 \)[/tex]) and bromine ([tex]\( Br_2 \)[/tex]) are both halogens, and they are in the activity series provided.
- The activity series tells us the relative reactivity of the halogens: [tex]\( F_2 > Cl_2 > Br_2 > I_2 \)[/tex].
3. Compare Reactivities (Activity Series):
- According to the activity series, iodine ([tex]\( I_2 \)[/tex]) is less reactive than bromine ([tex]\( Br_2 \)[/tex]).
4. Predict the Reaction:
- Since [tex]\( I_2 \)[/tex] is less reactive than [tex]\( Br_2 \)[/tex], [tex]\( I_2 \)[/tex] cannot displace [tex]\( Br \)[/tex] in [tex]\( NiBr_2 \)[/tex], so the reaction will not proceed.
Conclusion for Reaction 2:
- The reaction [tex]\( I_2 + NiBr_2 \rightarrow NiI_2 + Br_2 \)[/tex] will not take place.
### Final Prediction:
Based on the analysis:
- Reaction 1 ([tex]\( Cl_2 + 2 RbI \rightarrow 2 RbCl + I_2 \)[/tex]) will occur, indicated by 1.
- Reaction 2 ([tex]\( I_2 + NiBr_2 \rightarrow NiI_2 + Br_2 \)[/tex]) will not occur, indicated by 0.
Therefore, the expected results are:
[tex]\[ (1, 0) \][/tex]
Thank you for using this platform to share and learn. Keep asking and answering. We appreciate every contribution you make. For trustworthy answers, rely on IDNLearn.com. Thanks for visiting, and we look forward to assisting you again.
