IDNLearn.com connects you with a community of experts ready to answer your questions. Discover prompt and accurate responses from our experts, ensuring you get the information you need quickly.
Sagot :
Let's determine whether the given table represents a linear or nonlinear function. To do this, we need to analyze the rate of change (slope) between each pair of consecutive points.
Here is the table of points:
[tex]\[ \begin{tabular}{|c|c|} \hline $x$ & $y$ \\ \hline -2 & \frac{1}{-2} \\ \hline -1 & \frac{1}{3} \\ \hline 0 & 1 \\ \hline 1 & 3 \\ \hline 2 & 0 \\ \hline \end{tabular} \][/tex]
### Step-by-Step Calculation of the Rate of Change
1. Between [tex]$(-2, -\frac{1}{2})$[/tex] and [tex]$(-1, \frac{1}{3})$[/tex]:
[tex]\[ \Delta x = -1 - (-2) = 1, \quad \Delta y = \frac{1}{3} - \left(-\frac{1}{2}\right) = \frac{1}{3} + \frac{1}{2} = \frac{2}{6} + \frac{3}{6} = \frac{5}{6} \][/tex]
[tex]\[ \text{Rate of change} = \frac{\Delta y}{\Delta x} = \frac{\frac{5}{6}}{1} = \frac{5}{6} \approx 0.833 \][/tex]
2. Between [tex]$(-1, \frac{1}{3})$[/tex] and [tex]$(0, 1)$[/tex]:
[tex]\[ \Delta x = 0 - (-1) = 1, \quad \Delta y = 1 - \frac{1}{3} = \frac{3}{3} - \frac{1}{3} = \frac{2}{3} \][/tex]
[tex]\[ \text{Rate of change} = \frac{\Delta y}{\Delta x} = \frac{\frac{2}{3}}{1} = \frac{2}{3} \approx 0.667 \][/tex]
3. Between [tex]$(0, 1)$[/tex] and [tex]$(1, 3)$[/tex]:
[tex]\[ \Delta x = 1 - 0 = 1, \quad \Delta y = 3 - 1 = 2 \][/tex]
[tex]\[ \text{Rate of change} = \frac{\Delta y}{\Delta x} = \frac{2}{1} = 2 \][/tex]
4. Between [tex]$(1, 3)$[/tex] and [tex]$(2, 0)$[/tex]:
[tex]\[ \Delta x = 2 - 1 = 1, \quad \Delta y = 0 - 3 = -3 \][/tex]
[tex]\[ \text{Rate of change} = \frac{\Delta y}{\Delta x} = \frac{-3}{1} = -3 \][/tex]
### Analysis of Results
The calculated rates of change between each pair of points are:
1. Between [tex]$x = -2$[/tex] and [tex]$x = -1$[/tex]: Approximately 0.833
2. Between [tex]$x = -1$[/tex] and [tex]$x = 0$[/tex]: Approximately 0.667
3. Between [tex]$x = 0$[/tex] and [tex]$x = 1$[/tex]: Exactly 2
4. Between [tex]$x = 1$[/tex] and [tex]$x = 2$[/tex]: Exactly -3
Since the rate of change is not consistent (it varies between the pairs of points), the table does not represent a linear function because a linear function must have a constant rate of change (slope).
### Conclusion
Based on our analysis:
The table represents a nonlinear function because the rate of change is not constant.
Here is the table of points:
[tex]\[ \begin{tabular}{|c|c|} \hline $x$ & $y$ \\ \hline -2 & \frac{1}{-2} \\ \hline -1 & \frac{1}{3} \\ \hline 0 & 1 \\ \hline 1 & 3 \\ \hline 2 & 0 \\ \hline \end{tabular} \][/tex]
### Step-by-Step Calculation of the Rate of Change
1. Between [tex]$(-2, -\frac{1}{2})$[/tex] and [tex]$(-1, \frac{1}{3})$[/tex]:
[tex]\[ \Delta x = -1 - (-2) = 1, \quad \Delta y = \frac{1}{3} - \left(-\frac{1}{2}\right) = \frac{1}{3} + \frac{1}{2} = \frac{2}{6} + \frac{3}{6} = \frac{5}{6} \][/tex]
[tex]\[ \text{Rate of change} = \frac{\Delta y}{\Delta x} = \frac{\frac{5}{6}}{1} = \frac{5}{6} \approx 0.833 \][/tex]
2. Between [tex]$(-1, \frac{1}{3})$[/tex] and [tex]$(0, 1)$[/tex]:
[tex]\[ \Delta x = 0 - (-1) = 1, \quad \Delta y = 1 - \frac{1}{3} = \frac{3}{3} - \frac{1}{3} = \frac{2}{3} \][/tex]
[tex]\[ \text{Rate of change} = \frac{\Delta y}{\Delta x} = \frac{\frac{2}{3}}{1} = \frac{2}{3} \approx 0.667 \][/tex]
3. Between [tex]$(0, 1)$[/tex] and [tex]$(1, 3)$[/tex]:
[tex]\[ \Delta x = 1 - 0 = 1, \quad \Delta y = 3 - 1 = 2 \][/tex]
[tex]\[ \text{Rate of change} = \frac{\Delta y}{\Delta x} = \frac{2}{1} = 2 \][/tex]
4. Between [tex]$(1, 3)$[/tex] and [tex]$(2, 0)$[/tex]:
[tex]\[ \Delta x = 2 - 1 = 1, \quad \Delta y = 0 - 3 = -3 \][/tex]
[tex]\[ \text{Rate of change} = \frac{\Delta y}{\Delta x} = \frac{-3}{1} = -3 \][/tex]
### Analysis of Results
The calculated rates of change between each pair of points are:
1. Between [tex]$x = -2$[/tex] and [tex]$x = -1$[/tex]: Approximately 0.833
2. Between [tex]$x = -1$[/tex] and [tex]$x = 0$[/tex]: Approximately 0.667
3. Between [tex]$x = 0$[/tex] and [tex]$x = 1$[/tex]: Exactly 2
4. Between [tex]$x = 1$[/tex] and [tex]$x = 2$[/tex]: Exactly -3
Since the rate of change is not consistent (it varies between the pairs of points), the table does not represent a linear function because a linear function must have a constant rate of change (slope).
### Conclusion
Based on our analysis:
The table represents a nonlinear function because the rate of change is not constant.
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Thank you for visiting IDNLearn.com. We’re here to provide clear and concise answers, so visit us again soon.