Answered

IDNLearn.com offers a unique blend of expert answers and community insights. Ask anything and receive immediate, well-informed answers from our dedicated community of experts.

Select the correct answer:

Robert is a 15-year-old boy. His recommended dietary intake for vitamins B12, C, and E is 2.4 μg/day, 75 mg/day, and 15 mg/day, respectively. He eats a salmon fillet with one cup of boiled green beans and half a cup of fresh sliced strawberries for lunch. For which vitamins did Robert meet at least 75% of his recommended daily allowance?

| | Vitamin B12 | Vitamin C | Vitamin E |
|-----------------|-------------|-----------|-----------|
| Salmon fillet (124 g) | 5.87 μg | 0.0 mg | 0.60 mg |
| Boiled green beans (1 cup) | 0.0 μg | 12.1 mg | 0.57 mg |
| Strawberries, sliced (1/2 cup) | 0.0 μg | 49.0 mg | 0.42 mg |

A. Vitamin B12, Vitamin C, and Vitamin E
B. Vitamin B12 and Vitamin C only
C. Vitamin B12 and Vitamin E only
D. Vitamin C and Vitamin E only
E. Vitamin B12 only

Sagot :

GinnyAnsweridn
To determine for which vitamins Robert met at least 75% of his recommended daily allowance, let's analyze his intake for each vitamin.

1. Vitamin B12:
- Recommended daily allowance: 2.4 micrograms.
- Intake from salmon fillet: 5.87 micrograms.
- Intake from boiled green beans: 0.0 micrograms.
- Intake from strawberries: 0.0 micrograms.
- Total intake: [tex]\( 5.87 + 0.0 + 0.0 = 5.87 \)[/tex] micrograms.
- Percentage of daily allowance: [tex]\( \frac{5.87}{2.4} \times 100 \approx 244.58\% \)[/tex].

2. Vitamin C:
- Recommended daily allowance: 75 mg.
- Intake from salmon fillet: 0.0 mg.
- Intake from boiled green beans: 12.1 mg.
- Intake from strawberries: 49.0 mg.
- Total intake: [tex]\( 0.0 + 12.1 + 49.0 = 61.1 \)[/tex] mg.
- Percentage of daily allowance: [tex]\( \frac{61.1}{75} \times 100 \approx 81.47\% \)[/tex].

3. Vitamin E:
- Recommended daily allowance: 15 mg.
- Intake from salmon fillet: 0.60 mg.
- Intake from boiled green beans: 0.57 mg.
- Intake from strawberries: 0.42 mg.
- Total intake: [tex]\( 0.60 + 0.57 + 0.42 = 1.59 \)[/tex] mg.
- Percentage of daily allowance: [tex]\( \frac{1.59}{15} \times 100 \approx 10.6\% \)[/tex].

From the calculations:
- Vitamin B12 intake is approximately 244.58% of the recommended daily allowance, which is well above 75%.
- Vitamin C intake is approximately 81.47% of the recommended daily allowance, which is above 75%.
- Vitamin E intake is approximately 10.6% of the recommended daily allowance, which is below 75%.

Therefore, Robert met at least 75% of his recommended daily allowance for Vitamin B12 and Vitamin C only.

The correct answer is:
B. Vitamin B12 and Vitamin C only
Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! Discover insightful answers at IDNLearn.com. We appreciate your visit and look forward to assisting you again.