Discover how IDNLearn.com can help you learn and grow with its extensive Q&A platform. Explore a wide array of topics and find reliable answers from our experienced community members.
Sagot :
Answer:
(-3, -2)
(-1, -2)
(1, -2)
Step-by-step explanation:
To determine which points are solutions to the linear inequality y < 0.5x + 2, we need to check each point by substituting the x and y coordinates into the inequality.
Given points:
- (-3, -2)
- (-2, 1)
- (-1, -2)
- (-1, 2)
- (1, -2)
Let's test each point:
For point (-3, -2):
[tex]y < 0.5x + 2 \\\\-2 < 0.5(-3) + 2 \\\\-2 < -1.5 + 2 \\\\-2 < 0.5 \quad \text{(True)}[/tex]
For point (-2, 1):
[tex]y < 0.5x + 2 \\\\1 < 0.5(-2) + 2 \\\\1 < -1 + 2 \\\\1 < 1 \quad \text{(False)}[/tex]
For point (-1, -2):
[tex]y < 0.5x + 2 \\\\-2 < 0.5(-1) + 2 \\\\-2 < -0.5 + 2 \\\\-2 < 1.5 \quad \text{(True)}[/tex]
For point (-1, 2):
[tex]y < 0.5x + 2 \\\\2 < 0.5(-1) + 2 \\\\2 < -0.5 + 2 \\\\2 < 1.5 \quad \text{(False)}[/tex]
For point (1, -2):
[tex]y < 0.5x + 2 \\\\-2 < 0.5(1) + 2 \\\\-2 < 0.5 + 2 \\\\-2 < 2.5 \quad \text{(True)}[/tex]
Therefore, the points that are solutions to the inequality y < 0.5x + 2 are:
- (-3, -2)
- (-1, -2)
- (1, -2)
When determining solutions using the graph of the given inequality:
- Points inside the shaded region satisfy the inequality and are solutions.
- Points on the boundary line do not satisfy the inequality and are not solutions because the inequality is strict (< or >).
- Points outside the shaded region do not satisfy the inequality and are not solutions.

We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. Accurate answers are just a click away at IDNLearn.com. Thanks for stopping by, and come back for more reliable solutions.