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Calculate the following statistics for the given data:

| Weight of Cedartown Pumpkins (pounds) | Weight of Baytown Pumpkins (pounds) |
|-------------------------------------------|-----------------------------------------|
| 611 | 584 |
| 753 | 622 |
| 575 | 713.5 |
| 685.5 | 579 |
| 718 | 644 |

1. The average weight of pumpkins grown in Cedartown: __________
2. The average weight of pumpkins grown in Baytown: __________
3. The mean absolute deviation of the pumpkin weights in Cedartown: __________
4. The mean absolute deviation of the pumpkin weights in Baytown: __________

Sagot :

GinnyAnsweridn
Let's break down the solution step-by-step for the given problem, using the weights of the pumpkins from Cedartown and Baytown.

### Step 1: Calculate the Average Weight

#### Cedartown Pumpkins
The weights of the Cedartown pumpkins are:
611, 753, 575, 685.5, 718

To find the average weight of Cedartown pumpkins, we sum these weights and divide by the number of pumpkins.

[tex]\[ \text{Average weight of Cedartown pumpkins} = \frac{611 + 753 + 575 + 685.5 + 718}{5} = 668.5 \text{ pounds} \][/tex]

#### Baytown Pumpkins
The weights of the Baytown pumpkins are:
584, 622, 713.5, 579, 644

Similarly, to find the average weight of Baytown pumpkins, we sum these weights and divide by the number of pumpkins.

[tex]\[ \text{Average weight of Baytown pumpkins} = \frac{584 + 622 + 713.5 + 579 + 644}{5} = 628.5 \text{ pounds} \][/tex]

### Step 2: Calculate the Mean Absolute Deviation (MAD)

#### Cedartown Pumpkins MAD
First, we calculate the absolute deviations from the average:

[tex]\[ \begin{align*} |611 - 668.5| &= 57.5 \\ |753 - 668.5| &= 84.5 \\ |575 - 668.5| &= 93.5 \\ |685.5 - 668.5| &= 17.0 \\ |718 - 668.5| &= 49.5 \\ \end{align*} \][/tex]

Next, we find the average of these absolute deviations:

[tex]\[ \text{MAD of Cedartown pumpkins} = \frac{57.5 + 84.5 + 93.5 + 17.0 + 49.5}{5} = 60.4 \][/tex]

#### Baytown Pumpkins MAD
For the Baytown pumpkins, calculate the absolute deviations from the average:

[tex]\[ \begin{align*} |584 - 628.5| &= 44.5 \\ |622 - 628.5| &= 6.5 \\ |713.5 - 628.5| &= 85.0 \\ |579 - 628.5| &= 49.5 \\ |644 - 628.5| &= 15.5 \\ \end{align*} \][/tex]

Next, we find the average of these absolute deviations:

[tex]\[ \text{MAD of Baytown pumpkins} = \frac{44.5 + 6.5 + 85.0 + 49.5 + 15.5}{5} = 40.2 \][/tex]

### Final Results

Based on the calculations:

- The average weight of pumpkins grown in Cedartown is [tex]\(668.5 \text{ pounds}\)[/tex].
- The average weight of pumpkins grown in Baytown is [tex]\(628.5 \text{ pounds}\)[/tex].
- The mean absolute deviation of the pumpkin weights in Cedartown is [tex]\(60.4\)[/tex].
- The mean absolute deviation of the pumpkin weights in Baytown is [tex]\(40.2\)[/tex].
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