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What is the final speed of a bicyclist initially moving at 7 m/s who accelerates at a rate of 6 m/s2 for 4 seconds

Sagot :

Final speed of the bicyclist is 31 m/s.


We are given the initial speed of the bicyclist along with their acceleration. In this case the acceleration is uniform and linear.

Initial speed = 7 m/s

Acceleration = 6 m/s^2

Duration = 4 seconds

Final speed = Initial speed + Acceleration × Duration

Final speed = 7 m/s + 6 m/s^2 × 4 s

Final speed = 7 m/s + 24 m/s

Final speed = 31 m/s

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