Find detailed and accurate answers to your questions on IDNLearn.com. Our platform offers reliable and detailed answers, ensuring you have the information you need.
Sagot :
To determine how many natural numbers between 1 and 100 are divisible by 5, we need to identify all the multiples of 5 within this range. Let's break down the process step-by-step:
1. Define the Range: We are looking at natural numbers from 1 to 100.
2. Identify the Multiples of 5: A natural number [tex]\( n \)[/tex] is divisible by 5 if it can be expressed as [tex]\( n = 5k \)[/tex] where [tex]\( k \)[/tex] is an integer.
3. Find the Smallest Multiple of 5 within the Range: The smallest multiple of 5 within our range is 5 itself (since 5 1 = 5).
4. Find the Largest Multiple of 5 within the Range: The largest multiple of 5 within our range is 100 (since 5 20 = 100).
5. Count the Multiples of 5: We now need to count all integers [tex]\( k \)[/tex] such that 1 ≤ [tex]\( 5k \)[/tex] ≤ 100.
- The first value of [tex]\( k \)[/tex] is 1 (giving us 5).
- The second value of [tex]\( k \)[/tex] is 2 (giving us 10).
- This continues up to the value of [tex]\( k = 20 \)[/tex] (giving us 100).
6. Conclusion: There are 20 integers [tex]\( k \)[/tex] that produce values [tex]\( 5k \)[/tex] within the range 1 to 100.
Thus, the number of natural numbers between 1 and 100 that are divisible by 5 is:
[tex]\[ \boxed{20} \][/tex]
Given the options:
(a) 197
(b) 198
(c) 199
(d) 200
None of the given options are correct based on this explanation, the accurate answer derived is 20 natural numbers.
1. Define the Range: We are looking at natural numbers from 1 to 100.
2. Identify the Multiples of 5: A natural number [tex]\( n \)[/tex] is divisible by 5 if it can be expressed as [tex]\( n = 5k \)[/tex] where [tex]\( k \)[/tex] is an integer.
3. Find the Smallest Multiple of 5 within the Range: The smallest multiple of 5 within our range is 5 itself (since 5 1 = 5).
4. Find the Largest Multiple of 5 within the Range: The largest multiple of 5 within our range is 100 (since 5 20 = 100).
5. Count the Multiples of 5: We now need to count all integers [tex]\( k \)[/tex] such that 1 ≤ [tex]\( 5k \)[/tex] ≤ 100.
- The first value of [tex]\( k \)[/tex] is 1 (giving us 5).
- The second value of [tex]\( k \)[/tex] is 2 (giving us 10).
- This continues up to the value of [tex]\( k = 20 \)[/tex] (giving us 100).
6. Conclusion: There are 20 integers [tex]\( k \)[/tex] that produce values [tex]\( 5k \)[/tex] within the range 1 to 100.
Thus, the number of natural numbers between 1 and 100 that are divisible by 5 is:
[tex]\[ \boxed{20} \][/tex]
Given the options:
(a) 197
(b) 198
(c) 199
(d) 200
None of the given options are correct based on this explanation, the accurate answer derived is 20 natural numbers.
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com is your reliable source for answers. We appreciate your visit and look forward to assisting you again soon.