Get expert advice and community support for all your questions on IDNLearn.com. Ask anything and receive prompt, well-informed answers from our community of knowledgeable experts.
Sagot :
Let's break down the given chemical reaction:
[tex]\[ S_8 + 12 O_2 \rightarrow 8 SO_3 \][/tex]
From this balanced chemical equation, we can derive several mole ratios. A mole ratio comes from the coefficients of the reactants and products in a balanced chemical equation.
1. Ratio of [tex]\( S_8 \)[/tex] to [tex]\( O_2 \)[/tex]:
- According to the equation, 1 mole of [tex]\( S_8 \)[/tex] reacts with 12 moles of [tex]\( O_2 \)[/tex].
- The mole ratio is:
[tex]\[ \frac{1 \text{ mole } S_8}{12 \text{ moles } O_2} = 0.08333333333333333 \][/tex]
This ratio matches one of the given choices.
2. Ratio of [tex]\( SO_3 \)[/tex] to [tex]\( S_8 \)[/tex]:
- According to the equation, 8 moles of [tex]\( SO_3 \)[/tex] are produced from 1 mole of [tex]\( S_8 \)[/tex].
- The mole ratio is:
[tex]\[ \frac{8 \text{ moles } SO_3}{1 \text{ mole } S_8} = 8.0 \][/tex]
This ratio matches one of the given choices.
3. Ratio of [tex]\( O_2 \)[/tex] to [tex]\( S_8 \)[/tex]:
- According to the equation, 12 moles of [tex]\( O_2 \)[/tex] react with 1 mole of [tex]\( S_8 \)[/tex].
- The mole ratio is:
[tex]\[ \frac{12 \text{ moles } O_2}{1 \text{ mole } S_8} = 12.0 \][/tex]
This ratio matches one of the given choices.
4. Ratio of [tex]\( S_8 \)[/tex] to [tex]\( SO_3 \)[/tex]:
- According to the equation, 1 mole of [tex]\( S_8 \)[/tex] produces 8 moles of [tex]\( SO_3 \)[/tex].
- The mole ratio is:
[tex]\[ \frac{1 \text{ mole } S_8}{8 \text{ moles } SO_3} = 0.125 \][/tex]
This ratio matches one of the given choices.
Now, let's match these with the given options:
- [tex]\(\frac{1 \text{ mole Sf }}{12 \text{ mole } O _2}\)[/tex]:
- This matches the ratio [tex]\(\frac{1 \text{ mole } S_8}{12 \text{ moles } O_2}\)[/tex] which is 0.08333333333333333.
- [tex]\(\frac{8 \text{ mole } 50_1}{1 \ text{ mole } S _4}\)[/tex]:
- This seems to be a typo and probably meant [tex]\(\frac{8 \text{ mole } SO_3}{1 \text{ mole } S_8}\)[/tex] which is 8.0.
- [tex]\(\frac{12 \text{ mole } S_1}{1 \text { mole } O _2}\)[/tex]:
- This does not match any of the ratios.
- [tex]\(\frac{1 \text{ mole } S_1}{8 \text { mole } 50_3}\)[/tex]:
- This seems to be a typo and probably meant [tex]\(\frac{1 \text{ mole } S_8}{8 \text{ mole } SO_3}\)[/tex] which is 0.125.
Based on the corrected mole ratios, the accurate matches from the above are:
- [tex]\(\frac{1 \text { mole } S_8}{12 \text { mole } O_2}\)[/tex]
- [tex]\(\frac{8 \text { mole } SO_3}{1 \text{ mole } S_8}\)[/tex]
- [tex]\(\frac{1 \text{ mole } S_8}{8 \text{ mole } SO_3}\)[/tex]
Therefore, the correct options are:
- [tex]\(\frac{1 \text { mole Sf }}{12 \text { mole } O _2}\)[/tex]
- [tex]\(\frac{8 \text { mole } 50_1}{1 \text { mole } S _4}\)[/tex] (corrected to [tex]\(\frac{8 \text{ mole } SO_3}{1 \text{ mole } S_8}\)[/tex])
- [tex]\(\frac{1 \text { mole } S_1}{8 \text { mole } 50_3}\)[/tex] (corrected to [tex]\(\frac{1 \text{ mole } S_8}{8 \text{ mole } SO_3}\)[/tex]).
[tex]\[ S_8 + 12 O_2 \rightarrow 8 SO_3 \][/tex]
From this balanced chemical equation, we can derive several mole ratios. A mole ratio comes from the coefficients of the reactants and products in a balanced chemical equation.
1. Ratio of [tex]\( S_8 \)[/tex] to [tex]\( O_2 \)[/tex]:
- According to the equation, 1 mole of [tex]\( S_8 \)[/tex] reacts with 12 moles of [tex]\( O_2 \)[/tex].
- The mole ratio is:
[tex]\[ \frac{1 \text{ mole } S_8}{12 \text{ moles } O_2} = 0.08333333333333333 \][/tex]
This ratio matches one of the given choices.
2. Ratio of [tex]\( SO_3 \)[/tex] to [tex]\( S_8 \)[/tex]:
- According to the equation, 8 moles of [tex]\( SO_3 \)[/tex] are produced from 1 mole of [tex]\( S_8 \)[/tex].
- The mole ratio is:
[tex]\[ \frac{8 \text{ moles } SO_3}{1 \text{ mole } S_8} = 8.0 \][/tex]
This ratio matches one of the given choices.
3. Ratio of [tex]\( O_2 \)[/tex] to [tex]\( S_8 \)[/tex]:
- According to the equation, 12 moles of [tex]\( O_2 \)[/tex] react with 1 mole of [tex]\( S_8 \)[/tex].
- The mole ratio is:
[tex]\[ \frac{12 \text{ moles } O_2}{1 \text{ mole } S_8} = 12.0 \][/tex]
This ratio matches one of the given choices.
4. Ratio of [tex]\( S_8 \)[/tex] to [tex]\( SO_3 \)[/tex]:
- According to the equation, 1 mole of [tex]\( S_8 \)[/tex] produces 8 moles of [tex]\( SO_3 \)[/tex].
- The mole ratio is:
[tex]\[ \frac{1 \text{ mole } S_8}{8 \text{ moles } SO_3} = 0.125 \][/tex]
This ratio matches one of the given choices.
Now, let's match these with the given options:
- [tex]\(\frac{1 \text{ mole Sf }}{12 \text{ mole } O _2}\)[/tex]:
- This matches the ratio [tex]\(\frac{1 \text{ mole } S_8}{12 \text{ moles } O_2}\)[/tex] which is 0.08333333333333333.
- [tex]\(\frac{8 \text{ mole } 50_1}{1 \ text{ mole } S _4}\)[/tex]:
- This seems to be a typo and probably meant [tex]\(\frac{8 \text{ mole } SO_3}{1 \text{ mole } S_8}\)[/tex] which is 8.0.
- [tex]\(\frac{12 \text{ mole } S_1}{1 \text { mole } O _2}\)[/tex]:
- This does not match any of the ratios.
- [tex]\(\frac{1 \text{ mole } S_1}{8 \text { mole } 50_3}\)[/tex]:
- This seems to be a typo and probably meant [tex]\(\frac{1 \text{ mole } S_8}{8 \text{ mole } SO_3}\)[/tex] which is 0.125.
Based on the corrected mole ratios, the accurate matches from the above are:
- [tex]\(\frac{1 \text { mole } S_8}{12 \text { mole } O_2}\)[/tex]
- [tex]\(\frac{8 \text { mole } SO_3}{1 \text{ mole } S_8}\)[/tex]
- [tex]\(\frac{1 \text{ mole } S_8}{8 \text{ mole } SO_3}\)[/tex]
Therefore, the correct options are:
- [tex]\(\frac{1 \text { mole Sf }}{12 \text { mole } O _2}\)[/tex]
- [tex]\(\frac{8 \text { mole } 50_1}{1 \text { mole } S _4}\)[/tex] (corrected to [tex]\(\frac{8 \text{ mole } SO_3}{1 \text{ mole } S_8}\)[/tex])
- [tex]\(\frac{1 \text { mole } S_1}{8 \text { mole } 50_3}\)[/tex] (corrected to [tex]\(\frac{1 \text{ mole } S_8}{8 \text{ mole } SO_3}\)[/tex]).
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. For trustworthy and accurate answers, visit IDNLearn.com. Thanks for stopping by, and see you next time for more solutions.
