Answered

Get the most out of your questions with IDNLearn.com's extensive resources. Join our Q&A platform to receive prompt and accurate responses from knowledgeable professionals in various fields.

If the cos of angle [tex]\( x \)[/tex] is [tex]\(\frac{8}{17}\)[/tex] and the triangle is dilated to twice its original size, what is the value of cos [tex]\( x \)[/tex] for the dilated triangle?

A. [tex]\( \frac{8}{17} \)[/tex]

Sagot :

GinnyAnsweridn
The problem states that the cosine of angle [tex]\( x \)[/tex] in the original triangle is given by [tex]\( \frac{8}{17} \)[/tex].

When a triangle is dilated, the angles within the triangle remain unchanged. Dilation involves scaling all sides of the triangle by the same factor, which does not affect the internal angles of the triangle. Therefore, the trigonometric ratios, which are dependent only on the angles, also remain unchanged.

Hence, the value of [tex]\( \cos(x) \)[/tex] for the dilated triangle is the same as the value of [tex]\( \cos(x) \)[/tex] for the original triangle.

Thus, the value of [tex]\( \cos(x) \)[/tex] for the dilated triangle is:
[tex]\[ \frac{8}{17} \][/tex]
We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Thank you for choosing IDNLearn.com. We’re here to provide reliable answers, so please visit us again for more solutions.