IDNLearn.com makes it easy to find precise answers to your specific questions. Discover in-depth answers to your questions from our community of experienced professionals.
Sagot :
To find the mean of the data summarized in the given frequency distribution, we will follow these steps:
1. Determine the midpoints for each interval:
- For the interval [tex]\(40-44\)[/tex], the midpoint is [tex]\((40 + 44) / 2 = 42\)[/tex].
- For the interval [tex]\(45-49\)[/tex], the midpoint is [tex]\((45 + 49) / 2 = 47\)[/tex].
- For the interval [tex]\(50-54\)[/tex], the midpoint is [tex]\((50 + 54) / 2 = 52\)[/tex].
- For the interval [tex]\(55-59\)[/tex], the midpoint is [tex]\((55 + 59) / 2 = 57\)[/tex].
- For the interval [tex]\(60-64\)[/tex], the midpoint is [tex]\((60 + 64) / 2 = 62\)[/tex].
2. List the midpoints and their corresponding frequencies:
[tex]\[ \begin{array}{cc} \text{Midpoint} & \text{Frequency} \\ \hline 42 & 3 \\ 47 & 6 \\ 52 & 12 \\ 57 & 7 \\ 62 & 3 \\ \end{array} \][/tex]
3. Calculate the weighted sum of the midpoints:
- Multiply each midpoint by its corresponding frequency and sum the results:
[tex]\[ (42 \times 3) + (47 \times 6) + (52 \times 12) + (57 \times 7) + (62 \times 3) \][/tex]
[tex]\[ = 126 + 282 + 624 + 399 + 186 \][/tex]
[tex]\[ = 1617 \][/tex]
4. Calculate the total number of data points:
- Sum the frequencies:
[tex]\[ 3 + 6 + 12 + 7 + 3 = 31 \][/tex]
5. Find the mean of the frequency distribution:
- Divide the weighted sum of the midpoints by the total number of data points:
[tex]\[ \text{Mean} = \frac{1617}{31} \approx 52.161 \][/tex]
- Rounded to the nearest tenth:
[tex]\[ \text{Mean} \approx 52.2 \][/tex]
So, the mean of the frequency distribution is approximately [tex]\(52.2\)[/tex] degrees.
When comparing this computed mean to the actual mean of [tex]\(56.4\)[/tex] degrees, we observe that the computed mean is lower. This indicates that the frequency distribution is somewhat skewed toward the lower intervals.
1. Determine the midpoints for each interval:
- For the interval [tex]\(40-44\)[/tex], the midpoint is [tex]\((40 + 44) / 2 = 42\)[/tex].
- For the interval [tex]\(45-49\)[/tex], the midpoint is [tex]\((45 + 49) / 2 = 47\)[/tex].
- For the interval [tex]\(50-54\)[/tex], the midpoint is [tex]\((50 + 54) / 2 = 52\)[/tex].
- For the interval [tex]\(55-59\)[/tex], the midpoint is [tex]\((55 + 59) / 2 = 57\)[/tex].
- For the interval [tex]\(60-64\)[/tex], the midpoint is [tex]\((60 + 64) / 2 = 62\)[/tex].
2. List the midpoints and their corresponding frequencies:
[tex]\[ \begin{array}{cc} \text{Midpoint} & \text{Frequency} \\ \hline 42 & 3 \\ 47 & 6 \\ 52 & 12 \\ 57 & 7 \\ 62 & 3 \\ \end{array} \][/tex]
3. Calculate the weighted sum of the midpoints:
- Multiply each midpoint by its corresponding frequency and sum the results:
[tex]\[ (42 \times 3) + (47 \times 6) + (52 \times 12) + (57 \times 7) + (62 \times 3) \][/tex]
[tex]\[ = 126 + 282 + 624 + 399 + 186 \][/tex]
[tex]\[ = 1617 \][/tex]
4. Calculate the total number of data points:
- Sum the frequencies:
[tex]\[ 3 + 6 + 12 + 7 + 3 = 31 \][/tex]
5. Find the mean of the frequency distribution:
- Divide the weighted sum of the midpoints by the total number of data points:
[tex]\[ \text{Mean} = \frac{1617}{31} \approx 52.161 \][/tex]
- Rounded to the nearest tenth:
[tex]\[ \text{Mean} \approx 52.2 \][/tex]
So, the mean of the frequency distribution is approximately [tex]\(52.2\)[/tex] degrees.
When comparing this computed mean to the actual mean of [tex]\(56.4\)[/tex] degrees, we observe that the computed mean is lower. This indicates that the frequency distribution is somewhat skewed toward the lower intervals.
Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. Accurate answers are just a click away at IDNLearn.com. Thanks for stopping by, and come back for more reliable solutions.