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how to find the equation of the line through the point (3,-5) which is parallel to the line with equation 3x+2y-5=0

Sagot :

Answer:

Step-by-step explanation:

3x + 2y - 5 = 0      re-arrange to  y = mx + b form :

y =  -3/2 x + 5/3     slope is m = - 3/2

                               parallel slope is the same value

so...the start of your new line is

  y = - 3/2 x + b        substitute in the gieven point to calculate 'b'

  - 5 =  - 3/2 ( 3) + b

            b = - 1/2

You requested line is then

       y = - 3/2 x - 1/2

Here is a picture:

View image Jsimpson11000
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