IDNLearn.com offers a unique blend of expert answers and community-driven knowledge. Join our community to receive prompt and reliable responses to your questions from experienced professionals.
Sagot :
Let's analyze each of the given statements about the function [tex]\( y = \left(\frac{1}{3}\right)^x \)[/tex] one by one:
1. The function is increasing:
To determine whether the function is increasing or decreasing, we need to look at the base of the exponential function. The function [tex]\( y = a^x \)[/tex] is increasing if [tex]\( a > 1 \)[/tex] and decreasing if [tex]\( 0 < a < 1 \)[/tex]. In our case, the base is [tex]\( \frac{1}{3} \)[/tex], which is less than 1 but greater than 0. Hence, the function is decreasing for all real [tex]\( x \)[/tex].
Conclusion: The statement "The function is increasing" is false.
2. The function is decreasing:
As discussed in the previous point, because [tex]\( 0 < \frac{1}{3} < 1 \)[/tex], the function [tex]\( y = \left(\frac{1}{3}\right)^x \)[/tex] is indeed a decreasing function for all real [tex]\( x \)[/tex].
Conclusion: The statement "The function is decreasing" is true.
3. The [tex]\( x \)[/tex]-intercept is [tex]\( (1,0) \)[/tex]:
To find the [tex]\( x \)[/tex]-intercept, we need to set [tex]\( y = 0 \)[/tex] and solve for [tex]\( x \)[/tex]. However, the function [tex]\( y = \left(\frac{1}{3}\right)^x \)[/tex] is never equal to zero for any real [tex]\( x \)[/tex] because the exponential function with a positive base never actually reaches zero; it only gets closer and closer to zero as [tex]\( x \to \infty \)[/tex].
Conclusion: The statement "The [tex]\( x \)[/tex]-intercept is [tex]\( (1,0) \)[/tex]" is false.
4. The [tex]\( y \)[/tex]-intercept is [tex]\( (0,1) \)[/tex]:
To find the [tex]\( y \)[/tex]-intercept, we set [tex]\( x = 0 \)[/tex] and solve for [tex]\( y \)[/tex]. Plugging [tex]\( x = 0 \)[/tex] into the function [tex]\( y = \left(\frac{1}{3}\right)^x \)[/tex] gives us:
[tex]\[ y = \left(\frac{1}{3}\right)^0 = 1. \][/tex]
Therefore, the [tex]\( y \)[/tex]-intercept is indeed [tex]\( (0,1) \)[/tex].
Conclusion: The statement "The [tex]\( y \)[/tex]-intercept is [tex]\( (0,1) \)[/tex]" is true.
5. The range of the function is all real numbers:
The range of the exponential function [tex]\( y = \left(\frac{1}{3}\right)^x \)[/tex] is the set of all possible output values. Since [tex]\( \left(\frac{1}{3}\right)^x \)[/tex] is always a positive number regardless of the value of [tex]\( x \)[/tex], the range is [tex]\( (0, \infty) \)[/tex], not all real numbers.
Conclusion: The statement "The range of the function is all real numbers" is false.
To summarize:
- The function is increasing: False
- The function is decreasing: True
- The [tex]\( x \)[/tex]-intercept is [tex]\( (1,0) \)[/tex]: False
- The [tex]\( y \)[/tex]-intercept is [tex]\( (0,1) \)[/tex]: True
- The range of the function is all real numbers: False
1. The function is increasing:
To determine whether the function is increasing or decreasing, we need to look at the base of the exponential function. The function [tex]\( y = a^x \)[/tex] is increasing if [tex]\( a > 1 \)[/tex] and decreasing if [tex]\( 0 < a < 1 \)[/tex]. In our case, the base is [tex]\( \frac{1}{3} \)[/tex], which is less than 1 but greater than 0. Hence, the function is decreasing for all real [tex]\( x \)[/tex].
Conclusion: The statement "The function is increasing" is false.
2. The function is decreasing:
As discussed in the previous point, because [tex]\( 0 < \frac{1}{3} < 1 \)[/tex], the function [tex]\( y = \left(\frac{1}{3}\right)^x \)[/tex] is indeed a decreasing function for all real [tex]\( x \)[/tex].
Conclusion: The statement "The function is decreasing" is true.
3. The [tex]\( x \)[/tex]-intercept is [tex]\( (1,0) \)[/tex]:
To find the [tex]\( x \)[/tex]-intercept, we need to set [tex]\( y = 0 \)[/tex] and solve for [tex]\( x \)[/tex]. However, the function [tex]\( y = \left(\frac{1}{3}\right)^x \)[/tex] is never equal to zero for any real [tex]\( x \)[/tex] because the exponential function with a positive base never actually reaches zero; it only gets closer and closer to zero as [tex]\( x \to \infty \)[/tex].
Conclusion: The statement "The [tex]\( x \)[/tex]-intercept is [tex]\( (1,0) \)[/tex]" is false.
4. The [tex]\( y \)[/tex]-intercept is [tex]\( (0,1) \)[/tex]:
To find the [tex]\( y \)[/tex]-intercept, we set [tex]\( x = 0 \)[/tex] and solve for [tex]\( y \)[/tex]. Plugging [tex]\( x = 0 \)[/tex] into the function [tex]\( y = \left(\frac{1}{3}\right)^x \)[/tex] gives us:
[tex]\[ y = \left(\frac{1}{3}\right)^0 = 1. \][/tex]
Therefore, the [tex]\( y \)[/tex]-intercept is indeed [tex]\( (0,1) \)[/tex].
Conclusion: The statement "The [tex]\( y \)[/tex]-intercept is [tex]\( (0,1) \)[/tex]" is true.
5. The range of the function is all real numbers:
The range of the exponential function [tex]\( y = \left(\frac{1}{3}\right)^x \)[/tex] is the set of all possible output values. Since [tex]\( \left(\frac{1}{3}\right)^x \)[/tex] is always a positive number regardless of the value of [tex]\( x \)[/tex], the range is [tex]\( (0, \infty) \)[/tex], not all real numbers.
Conclusion: The statement "The range of the function is all real numbers" is false.
To summarize:
- The function is increasing: False
- The function is decreasing: True
- The [tex]\( x \)[/tex]-intercept is [tex]\( (1,0) \)[/tex]: False
- The [tex]\( y \)[/tex]-intercept is [tex]\( (0,1) \)[/tex]: True
- The range of the function is all real numbers: False
We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Thank you for choosing IDNLearn.com. We’re here to provide reliable answers, so please visit us again for more solutions.