IDNLearn.com provides a user-friendly platform for finding answers to your questions. Our experts provide accurate and detailed responses to help you navigate any topic or issue with confidence.
Sagot :
Let's analyze each of the given statements about the function [tex]\( y = \left(\frac{1}{3}\right)^x \)[/tex] one by one:
1. The function is increasing:
To determine whether the function is increasing or decreasing, we need to look at the base of the exponential function. The function [tex]\( y = a^x \)[/tex] is increasing if [tex]\( a > 1 \)[/tex] and decreasing if [tex]\( 0 < a < 1 \)[/tex]. In our case, the base is [tex]\( \frac{1}{3} \)[/tex], which is less than 1 but greater than 0. Hence, the function is decreasing for all real [tex]\( x \)[/tex].
Conclusion: The statement "The function is increasing" is false.
2. The function is decreasing:
As discussed in the previous point, because [tex]\( 0 < \frac{1}{3} < 1 \)[/tex], the function [tex]\( y = \left(\frac{1}{3}\right)^x \)[/tex] is indeed a decreasing function for all real [tex]\( x \)[/tex].
Conclusion: The statement "The function is decreasing" is true.
3. The [tex]\( x \)[/tex]-intercept is [tex]\( (1,0) \)[/tex]:
To find the [tex]\( x \)[/tex]-intercept, we need to set [tex]\( y = 0 \)[/tex] and solve for [tex]\( x \)[/tex]. However, the function [tex]\( y = \left(\frac{1}{3}\right)^x \)[/tex] is never equal to zero for any real [tex]\( x \)[/tex] because the exponential function with a positive base never actually reaches zero; it only gets closer and closer to zero as [tex]\( x \to \infty \)[/tex].
Conclusion: The statement "The [tex]\( x \)[/tex]-intercept is [tex]\( (1,0) \)[/tex]" is false.
4. The [tex]\( y \)[/tex]-intercept is [tex]\( (0,1) \)[/tex]:
To find the [tex]\( y \)[/tex]-intercept, we set [tex]\( x = 0 \)[/tex] and solve for [tex]\( y \)[/tex]. Plugging [tex]\( x = 0 \)[/tex] into the function [tex]\( y = \left(\frac{1}{3}\right)^x \)[/tex] gives us:
[tex]\[ y = \left(\frac{1}{3}\right)^0 = 1. \][/tex]
Therefore, the [tex]\( y \)[/tex]-intercept is indeed [tex]\( (0,1) \)[/tex].
Conclusion: The statement "The [tex]\( y \)[/tex]-intercept is [tex]\( (0,1) \)[/tex]" is true.
5. The range of the function is all real numbers:
The range of the exponential function [tex]\( y = \left(\frac{1}{3}\right)^x \)[/tex] is the set of all possible output values. Since [tex]\( \left(\frac{1}{3}\right)^x \)[/tex] is always a positive number regardless of the value of [tex]\( x \)[/tex], the range is [tex]\( (0, \infty) \)[/tex], not all real numbers.
Conclusion: The statement "The range of the function is all real numbers" is false.
To summarize:
- The function is increasing: False
- The function is decreasing: True
- The [tex]\( x \)[/tex]-intercept is [tex]\( (1,0) \)[/tex]: False
- The [tex]\( y \)[/tex]-intercept is [tex]\( (0,1) \)[/tex]: True
- The range of the function is all real numbers: False
1. The function is increasing:
To determine whether the function is increasing or decreasing, we need to look at the base of the exponential function. The function [tex]\( y = a^x \)[/tex] is increasing if [tex]\( a > 1 \)[/tex] and decreasing if [tex]\( 0 < a < 1 \)[/tex]. In our case, the base is [tex]\( \frac{1}{3} \)[/tex], which is less than 1 but greater than 0. Hence, the function is decreasing for all real [tex]\( x \)[/tex].
Conclusion: The statement "The function is increasing" is false.
2. The function is decreasing:
As discussed in the previous point, because [tex]\( 0 < \frac{1}{3} < 1 \)[/tex], the function [tex]\( y = \left(\frac{1}{3}\right)^x \)[/tex] is indeed a decreasing function for all real [tex]\( x \)[/tex].
Conclusion: The statement "The function is decreasing" is true.
3. The [tex]\( x \)[/tex]-intercept is [tex]\( (1,0) \)[/tex]:
To find the [tex]\( x \)[/tex]-intercept, we need to set [tex]\( y = 0 \)[/tex] and solve for [tex]\( x \)[/tex]. However, the function [tex]\( y = \left(\frac{1}{3}\right)^x \)[/tex] is never equal to zero for any real [tex]\( x \)[/tex] because the exponential function with a positive base never actually reaches zero; it only gets closer and closer to zero as [tex]\( x \to \infty \)[/tex].
Conclusion: The statement "The [tex]\( x \)[/tex]-intercept is [tex]\( (1,0) \)[/tex]" is false.
4. The [tex]\( y \)[/tex]-intercept is [tex]\( (0,1) \)[/tex]:
To find the [tex]\( y \)[/tex]-intercept, we set [tex]\( x = 0 \)[/tex] and solve for [tex]\( y \)[/tex]. Plugging [tex]\( x = 0 \)[/tex] into the function [tex]\( y = \left(\frac{1}{3}\right)^x \)[/tex] gives us:
[tex]\[ y = \left(\frac{1}{3}\right)^0 = 1. \][/tex]
Therefore, the [tex]\( y \)[/tex]-intercept is indeed [tex]\( (0,1) \)[/tex].
Conclusion: The statement "The [tex]\( y \)[/tex]-intercept is [tex]\( (0,1) \)[/tex]" is true.
5. The range of the function is all real numbers:
The range of the exponential function [tex]\( y = \left(\frac{1}{3}\right)^x \)[/tex] is the set of all possible output values. Since [tex]\( \left(\frac{1}{3}\right)^x \)[/tex] is always a positive number regardless of the value of [tex]\( x \)[/tex], the range is [tex]\( (0, \infty) \)[/tex], not all real numbers.
Conclusion: The statement "The range of the function is all real numbers" is false.
To summarize:
- The function is increasing: False
- The function is decreasing: True
- The [tex]\( x \)[/tex]-intercept is [tex]\( (1,0) \)[/tex]: False
- The [tex]\( y \)[/tex]-intercept is [tex]\( (0,1) \)[/tex]: True
- The range of the function is all real numbers: False
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com is your go-to source for accurate answers. Thanks for stopping by, and come back for more helpful information.