Connect with knowledgeable experts and enthusiasts on IDNLearn.com. Our experts are available to provide accurate, comprehensive answers to help you make informed decisions about any topic or issue you encounter.
Sagot :
To determine whether the function [tex]\( f(x) = x^2 \)[/tex] increases or decreases when [tex]\( x > 1 \)[/tex], we can analyze its derivative.
1. Define the function:
[tex]\[ f(x) = x^2 \][/tex]
2. Compute the derivative of [tex]\( f(x) \)[/tex]:
Using the power rule for differentiation, which states that the derivative of [tex]\( x^n \)[/tex] is [tex]\( nx^{n-1} \)[/tex], we find:
[tex]\[ f'(x) = \frac{d}{dx}(x^2) = 2x \][/tex]
3. Analyze the sign of the derivative for [tex]\( x > 1 \)[/tex]:
We need to check the value of [tex]\( f'(x) \)[/tex] when [tex]\( x > 1 \)[/tex]. Specifically:
[tex]\[ f'(x) = 2x \][/tex]
For [tex]\( x > 1 \)[/tex], let's consider a point slightly greater than 1, say [tex]\( x = 1.1 \)[/tex].
4. Substitute [tex]\( x = 1.1 \)[/tex] into the derivative:
[tex]\[ f'(1.1) = 2 \times 1.1 = 2.2 \][/tex]
Since [tex]\( f'(1.1) = 2.2 \)[/tex] is positive, we can conclude that [tex]\( f(x) = x^2 \)[/tex] is increasing when [tex]\( x > 1 \)[/tex]. This is because the positive derivative indicates that the function's slope is positive, implying that the function is increasing in this interval.
1. Define the function:
[tex]\[ f(x) = x^2 \][/tex]
2. Compute the derivative of [tex]\( f(x) \)[/tex]:
Using the power rule for differentiation, which states that the derivative of [tex]\( x^n \)[/tex] is [tex]\( nx^{n-1} \)[/tex], we find:
[tex]\[ f'(x) = \frac{d}{dx}(x^2) = 2x \][/tex]
3. Analyze the sign of the derivative for [tex]\( x > 1 \)[/tex]:
We need to check the value of [tex]\( f'(x) \)[/tex] when [tex]\( x > 1 \)[/tex]. Specifically:
[tex]\[ f'(x) = 2x \][/tex]
For [tex]\( x > 1 \)[/tex], let's consider a point slightly greater than 1, say [tex]\( x = 1.1 \)[/tex].
4. Substitute [tex]\( x = 1.1 \)[/tex] into the derivative:
[tex]\[ f'(1.1) = 2 \times 1.1 = 2.2 \][/tex]
Since [tex]\( f'(1.1) = 2.2 \)[/tex] is positive, we can conclude that [tex]\( f(x) = x^2 \)[/tex] is increasing when [tex]\( x > 1 \)[/tex]. This is because the positive derivative indicates that the function's slope is positive, implying that the function is increasing in this interval.
Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. Find reliable answers at IDNLearn.com. Thanks for stopping by, and come back for more trustworthy solutions.