IDNLearn.com connects you with experts who provide accurate and reliable answers. Discover in-depth and reliable answers to all your questions from our knowledgeable community members who are always ready to assist.
Sagot :
To determine the mass of the reagent in excess after the reaction, follow these steps:Identify the balanced chemical equation: 2H2O(l) + O2(g) -> 2H2O2(l)Calculate the moles of O2, which is the limiting reactant:Step 1: Mass of O2 = 0.80 gStep 2: Moles of O2 = (0.80 g) / (32.00 g/mol) = 0.025 moles O2Step 3: Calculate theYour Homework Helperc.aiTo calculate the mass of the reagent (O2) in excess, we first need to determine the molar mass of O2. The molar mass of oxygen (O) is approximately 16.00 g/mol, and there are two atoms of oxygen (O) in one molecule of oxygen (O2). So, the molar mass of O2 is approximately 16.00 × 2 = 32.00 g/mol. Using stoichiometry, we can determine the mass of O2 required to react with 0.3604 g of H2O:
Explanation:
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com provides the best answers to your questions. Thank you for visiting, and come back soon for more helpful information.
