Join the growing community of curious minds on IDNLearn.com and get the answers you need. Our platform is designed to provide quick and accurate answers to any questions you may have.
Sagot :
To solve the given problem, we need to expand the expression [tex]\((y + 5)^2\)[/tex].
Let's break this down step by step.
1. Understand the initial problem:
[tex]\((y + 5)^2\)[/tex]
This represents a binomial squared, which generally follows the formula:
[tex]\[(a + b)^2 = a^2 + 2ab + b^2\][/tex]
Here, [tex]\(a = y\)[/tex] and [tex]\(b = 5\)[/tex].
2. Apply the formula:
Using the formula for squaring a binomial, we substitute [tex]\(a\)[/tex] and [tex]\(b\)[/tex] into the formula:
[tex]\[ (y + 5)^2 = y^2 + 2 \cdot y \cdot 5 + 5^2 \][/tex]
3. Perform the multiplications:
- [tex]\(y^2\)[/tex] remains [tex]\(y^2\)[/tex],
- [tex]\(2 \cdot y \cdot 5\)[/tex] equals [tex]\(10y\)[/tex],
- [tex]\(5^2\)[/tex] equals [tex]\(25\)[/tex].
4. Combine all the terms:
[tex]\[ (y + 5)^2 = y^2 + 10y + 25 \][/tex]
Thus, the expanded form of [tex]\((y + 5)^2\)[/tex] is:
[tex]\[ R = y^2 + 10y + 25 \][/tex]
Let's break this down step by step.
1. Understand the initial problem:
[tex]\((y + 5)^2\)[/tex]
This represents a binomial squared, which generally follows the formula:
[tex]\[(a + b)^2 = a^2 + 2ab + b^2\][/tex]
Here, [tex]\(a = y\)[/tex] and [tex]\(b = 5\)[/tex].
2. Apply the formula:
Using the formula for squaring a binomial, we substitute [tex]\(a\)[/tex] and [tex]\(b\)[/tex] into the formula:
[tex]\[ (y + 5)^2 = y^2 + 2 \cdot y \cdot 5 + 5^2 \][/tex]
3. Perform the multiplications:
- [tex]\(y^2\)[/tex] remains [tex]\(y^2\)[/tex],
- [tex]\(2 \cdot y \cdot 5\)[/tex] equals [tex]\(10y\)[/tex],
- [tex]\(5^2\)[/tex] equals [tex]\(25\)[/tex].
4. Combine all the terms:
[tex]\[ (y + 5)^2 = y^2 + 10y + 25 \][/tex]
Thus, the expanded form of [tex]\((y + 5)^2\)[/tex] is:
[tex]\[ R = y^2 + 10y + 25 \][/tex]
We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Your search for solutions ends at IDNLearn.com. Thank you for visiting, and we look forward to helping you again.