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Answer:
The sequence 12, 16, 24, 36, 52 forms an arithmetic progression with a common difference of 4. The nth term of an arithmetic progression can be expressed as:
an = a1 + (n-1)d
where a1 is the first term, n is the term number, and d is the common difference.
In this case, a1 = 12, d = 4, and the nth term can be expressed as:
an = 12 + (n-1)4