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Which equation can be simplified to find the inverse of [tex]\( y = 2x^2 \)[/tex]?

A. [tex]\( \frac{1}{y} = 2x^2 \)[/tex]

B. [tex]\( y = \frac{1}{2} x^2 \)[/tex]

C. [tex]\( -y = 2x^2 \)[/tex]

D. [tex]\( x = 2y^2 \)[/tex]


Sagot :

To find the inverse of the equation [tex]\( y = 2x^2 \)[/tex], we need to express [tex]\( x \)[/tex] in terms of [tex]\( y \)[/tex]. Follow these steps to derive the inverse:

1. Start with the original equation:
[tex]\[ y = 2x^2 \][/tex]

2. Solve for [tex]\( x^2 \)[/tex]:
[tex]\[ x^2 = \frac{y}{2} \][/tex]

3. Take the square root of both sides to solve for [tex]\( x \)[/tex]:
[tex]\[ x = \pm \sqrt{\frac{y}{2}} \][/tex]

Simplifying further:
[tex]\[ x = \pm \frac{\sqrt{2y}}{2} \][/tex]

This means we have two solutions, [tex]\( x = \frac{\sqrt{2y}}{2} \)[/tex] and [tex]\( x = -\frac{\sqrt{2y}}{2} \)[/tex].

4. Substitute back into the context to understand the inverse relationship:
[tex]\[ x = \pm \frac{\sqrt{2y}}{2} \][/tex]

Therefore, the equation that correctly represents the inverse of [tex]\( y = 2x^2 \)[/tex] when simplified would be:
[tex]\[ \boxed{x = \pm \frac{\sqrt{2y}}{2}} \][/tex]

Among the given options, the first three options can be rearranged and simplified, but none of them directly provide the inverse relationship. The fourth option [tex]\( x = 2y^2 \)[/tex] is incorrect since it does not align with our derived inverse. Thus, based on our derived step-by-step solution, we identify the simplified form for the inverse relationship. No given option correctly simplifies to the inverse; hence, the derived result ([tex]\( x = \pm \frac{\sqrt{2y}}{2} \)[/tex]) stands as the solution.