Join IDNLearn.com to access a wealth of knowledge and get your questions answered by experts. Find the answers you need quickly and accurately with help from our knowledgeable and dedicated community members.
Sagot :
Sure, let's balance the given chemical equation step-by-step:
The unbalanced equation is:
[tex]\[ \text{H}_2\text{O} + \text{Al}_2\text{O}_3 \rightarrow \text{Al(OH)}_3 \][/tex]
Step 1: List the number of atoms of each element on both sides of the reaction.
Initially, the unbalanced equation looks like this:
[tex]\[ \text{H}_2\text{O} + \text{Al}_2\text{O}_3 \rightarrow \text{Al(OH)}_3 \][/tex]
- On the left-hand side (LHS):
- [tex]\( \text{H}_2\text{O} \)[/tex] has 2 Hydrogen (H) atoms and 1 Oxygen (O) atom.
- [tex]\( \text{Al}_2\text{O}_3 \)[/tex] has 2 Aluminum (Al) atoms and 3 Oxygen (O) atoms.
- On the right-hand side (RHS):
- [tex]\( \text{Al(OH)}_3 \)[/tex] has 1 Aluminum (Al) atom, 3 Oxygen (O) atoms, and 3 Hydrogen (H) atoms.
Step 2: Balance the Aluminum (Al) atoms.
Since there are 2 Aluminum (Al) atoms in [tex]\( \text{Al}_2\text{O}_3 \)[/tex], you need 2 [tex]\( \text{Al(OH)}_3 \)[/tex] units on the RHS to balance the Al atoms.
[tex]\[ H_2O + \text{Al}_2\text{O}_3 \rightarrow 2 \cdot \text{Al(OH)}_3 \][/tex]
Now, RHS has 2 Aluminum (Al) atoms, 6 Oxygen (O) atoms (from 2 OH groups), and 6 Hydrogen (H) atoms (from 2 OH groups).
Step 3: Balance the Hydrogen (H) atoms.
You've got 6 Hydrogen (H) atoms on the RHS. To balance those, you need 6 Hydrogen atoms on the LHS. Each molecule of [tex]\( \text{H}_2\text{O} \)[/tex] has 2 Hydrogen atoms, so you need 3 [tex]\( \text{H}_2\text{O} \)[/tex] molecules on the LHS.
[tex]\[ 3H_2O + \text{Al}_2\text{O}_3 \rightarrow 2 \cdot \text{Al(OH)}_3 \][/tex]
Step 4: Balance the Oxygen (O) atoms.
On the LHS, you have:
- 3 Oxygen (O) atoms from [tex]\( \text{H}_2\text{O} \)[/tex]
- 3 Oxygen (O) atoms from [tex]\( \text{Al}_2\text{O}_3 \)[/tex]
So, 3 + 3 = 6 Oxygen atoms in total.
On the RHS:
- You have 6 Oxygen (O) atoms from [tex]\( 2 \times \text{Al(OH)}_3 \)[/tex].
Everything is balanced:
[tex]\[ 3H_2O + \text{Al}_2\text{O}_3 \rightarrow 2 \cdot \text{Al(OH)}_3 \][/tex]
Step 5: Correct the mistake
We notice that by accounting for 6 oxygen atoms, we are still left with 6 H atoms from 3 H2O molecules and only 6 H from 2 Al(OH)3. It turns out we haven't arrived at an imbalanced scenario with wrong counts. So, we need to redo our counts.
Hence, the balanced equation should always be checked for counts:
- Oxygen atoms on LHS: (6H2O = 6O) + 3 (Al2O3)
- Oxygen on RHS: 9 from 6-OH groups.
Hence, it's concluded that by trial verification, the most accurate tally is:
[tex]\[ 6H_2O + \text{Al}_2\text{O}_3 \rightarrow 2 \cdot \text{Al(OH)}_3 \][/tex]
So the balanced chemical equation is:
[tex]\[ 6H_2O + Al_2O_3 \rightarrow 2Al(OH)_3 \][/tex]
This equation shows that 6 molecules of water react with 1 formula unit of aluminum oxide to form 2 formula units of aluminum hydroxide!
The unbalanced equation is:
[tex]\[ \text{H}_2\text{O} + \text{Al}_2\text{O}_3 \rightarrow \text{Al(OH)}_3 \][/tex]
Step 1: List the number of atoms of each element on both sides of the reaction.
Initially, the unbalanced equation looks like this:
[tex]\[ \text{H}_2\text{O} + \text{Al}_2\text{O}_3 \rightarrow \text{Al(OH)}_3 \][/tex]
- On the left-hand side (LHS):
- [tex]\( \text{H}_2\text{O} \)[/tex] has 2 Hydrogen (H) atoms and 1 Oxygen (O) atom.
- [tex]\( \text{Al}_2\text{O}_3 \)[/tex] has 2 Aluminum (Al) atoms and 3 Oxygen (O) atoms.
- On the right-hand side (RHS):
- [tex]\( \text{Al(OH)}_3 \)[/tex] has 1 Aluminum (Al) atom, 3 Oxygen (O) atoms, and 3 Hydrogen (H) atoms.
Step 2: Balance the Aluminum (Al) atoms.
Since there are 2 Aluminum (Al) atoms in [tex]\( \text{Al}_2\text{O}_3 \)[/tex], you need 2 [tex]\( \text{Al(OH)}_3 \)[/tex] units on the RHS to balance the Al atoms.
[tex]\[ H_2O + \text{Al}_2\text{O}_3 \rightarrow 2 \cdot \text{Al(OH)}_3 \][/tex]
Now, RHS has 2 Aluminum (Al) atoms, 6 Oxygen (O) atoms (from 2 OH groups), and 6 Hydrogen (H) atoms (from 2 OH groups).
Step 3: Balance the Hydrogen (H) atoms.
You've got 6 Hydrogen (H) atoms on the RHS. To balance those, you need 6 Hydrogen atoms on the LHS. Each molecule of [tex]\( \text{H}_2\text{O} \)[/tex] has 2 Hydrogen atoms, so you need 3 [tex]\( \text{H}_2\text{O} \)[/tex] molecules on the LHS.
[tex]\[ 3H_2O + \text{Al}_2\text{O}_3 \rightarrow 2 \cdot \text{Al(OH)}_3 \][/tex]
Step 4: Balance the Oxygen (O) atoms.
On the LHS, you have:
- 3 Oxygen (O) atoms from [tex]\( \text{H}_2\text{O} \)[/tex]
- 3 Oxygen (O) atoms from [tex]\( \text{Al}_2\text{O}_3 \)[/tex]
So, 3 + 3 = 6 Oxygen atoms in total.
On the RHS:
- You have 6 Oxygen (O) atoms from [tex]\( 2 \times \text{Al(OH)}_3 \)[/tex].
Everything is balanced:
[tex]\[ 3H_2O + \text{Al}_2\text{O}_3 \rightarrow 2 \cdot \text{Al(OH)}_3 \][/tex]
Step 5: Correct the mistake
We notice that by accounting for 6 oxygen atoms, we are still left with 6 H atoms from 3 H2O molecules and only 6 H from 2 Al(OH)3. It turns out we haven't arrived at an imbalanced scenario with wrong counts. So, we need to redo our counts.
Hence, the balanced equation should always be checked for counts:
- Oxygen atoms on LHS: (6H2O = 6O) + 3 (Al2O3)
- Oxygen on RHS: 9 from 6-OH groups.
Hence, it's concluded that by trial verification, the most accurate tally is:
[tex]\[ 6H_2O + \text{Al}_2\text{O}_3 \rightarrow 2 \cdot \text{Al(OH)}_3 \][/tex]
So the balanced chemical equation is:
[tex]\[ 6H_2O + Al_2O_3 \rightarrow 2Al(OH)_3 \][/tex]
This equation shows that 6 molecules of water react with 1 formula unit of aluminum oxide to form 2 formula units of aluminum hydroxide!
Thank you for using this platform to share and learn. Keep asking and answering. We appreciate every contribution you make. Thank you for trusting IDNLearn.com with your questions. Visit us again for clear, concise, and accurate answers.
