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4x+3y=8 find the gradient

Sagot :

Semsee45idn

Answer:

[tex]-\dfrac{4}{3}[/tex]

Step-by-step explanation:

To find the gradient of the linear equation, 4x + 3y = 8, begin by rearranging the equation to isolate y:

[tex]4x+3y=8 \\\\\\4x+3y-4x=8-4x \\\\\\ 3y=-4x+8\\\\\\\dfrac{3y}{3}=\dfrac{-4+8}{3} \\\\\\y=-\dfrac{4}{3}x+\dfrac{8}{3}[/tex]

The equation is now in slope-intercept form, y = mx + b, where m is the slope (gradient), and b is the y-intercept.

By comparing the rearranged equation to the slope-intercept form, we can determine that the gradient (slope) of 4x + 3y = 8 is:

[tex]\LARGE\boxed{\boxed{-\dfrac{4}{3}}}[/tex]

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