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How many moles of KCl will be formed from 2.73 moles of KClO₃?

Given the reaction:
2 KClO₃ → 2 KCl + 3 O₂

A. 2.73 mol
B. 1.89 mol
C. 0.07 mol
D. 2.05 mol

Sagot :

GinnyAnsweridn
To determine how many moles of [tex]\( KCl \)[/tex] will be formed from 2.73 moles of [tex]\( KClO_3 \)[/tex], we need to look at the balanced chemical equation:

[tex]\[ 2 \, KClO_3 \rightarrow 2 \, KCl + 3 \, O_2 \][/tex]

This equation tells us that 2 moles of [tex]\( KClO_3 \)[/tex] produce 2 moles of [tex]\( KCl \)[/tex].

We can see that the stoichiometric ratio of [tex]\( KClO_3 \)[/tex] to [tex]\( KCl \)[/tex] is 1:1. This means that for every mole of [tex]\( KClO_3 \)[/tex] that reacts, one mole of [tex]\( KCl \)[/tex] is formed.

Since we have 2.73 moles of [tex]\( KClO_3 \)[/tex], it will produce an equivalent amount of [tex]\( KCl \)[/tex]. Hence, 2.73 moles of [tex]\( KClO_3 \)[/tex] will produce 2.73 moles of [tex]\( KCl \)[/tex].

Therefore, the number of moles of [tex]\( KCl \)[/tex] formed is:

[tex]\[ \boxed{2.73} \][/tex]

Thus, the correct answer is [tex]\( 2.73 \)[/tex] moles.
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