Explore a diverse range of topics and get answers from knowledgeable individuals on IDNLearn.com. Get the information you need from our experts, who provide reliable and detailed answers to all your questions.

Find the number of possible digits for [tex]\( x \)[/tex] such that [tex]\( 10x78x \)[/tex] is divisible by 3.

Sagot :

To determine the number of possible digits for [tex]\( x \)[/tex] such that the number [tex]\( 10x78x \)[/tex] is divisible by 3, we need to use the rule for divisibility by 3. According to this rule, a number is divisible by 3 if and only if the sum of its digits is divisible by 3.

Let's analyze the number [tex]\( 10x78x \)[/tex]:

1. The digits in the number are 1, 0, [tex]\( x \)[/tex], 7, 8, and [tex]\( x \)[/tex].
2. Summing these digits, we get:
[tex]\[ 1 + 0 + x + 7 + 8 + x \][/tex]
Simplifying the sum, we obtain:
[tex]\[ 1 + 0 + 7 + 8 + 2x = 16 + 2x \][/tex]

For [tex]\( 10x78x \)[/tex] to be divisible by 3, the sum [tex]\( 16 + 2x \)[/tex] must be divisible by 3.

We need to check each possible digit [tex]\( x \)[/tex] (from 0 to 9) to see which values make [tex]\( 16 + 2x \)[/tex] divisible by 3.

Let's go through each digit systematically:

- For [tex]\( x = 0 \)[/tex]:
[tex]\[ 16 + 2 \cdot 0 = 16 \quad (\text{not divisible by 3}) \][/tex]

- For [tex]\( x = 1 \)[/tex]:
[tex]\[ 16 + 2 \cdot 1 = 18 \quad (\text{divisible by 3}) \][/tex]

- For [tex]\( x = 2 \)[/tex]:
[tex]\[ 16 + 2 \cdot 2 = 20 \quad (\text{not divisible by 3}) \][/tex]

- For [tex]\( x = 3 \)[/tex]:
[tex]\[ 16 + 2 \cdot 3 = 22 \quad (\text{not divisible by 3}) \][/tex]

- For [tex]\( x = 4 \)[/tex]:
[tex]\[ 16 + 2 \cdot 4 = 24 \quad (\text{divisible by 3}) \][/tex]

- For [tex]\( x = 5 \)[/tex]:
[tex]\[ 16 + 2 \cdot 5 = 26 \quad (\text{not divisible by 3}) \][/tex]

- For [tex]\( x = 6 \)[/tex]:
[tex]\[ 16 + 2 \cdot 6 = 28 \quad (\text{not divisible by 3}) \][/tex]

- For [tex]\( x = 7 \)[/tex]:
[tex]\[ 16 + 2 \cdot 7 = 30 \quad (\text{divisible by 3}) \][/tex]

- For [tex]\( x = 8 \)[/tex]:
[tex]\[ 16 + 2 \cdot 8 = 32 \quad (\text{not divisible by 3}) \][/tex]

- For [tex]\( x = 9 \)[/tex]:
[tex]\[ 16 + 2 \cdot 9 = 34 \quad (\text{not divisible by 3}) \][/tex]

From this evaluation, we see that the values of [tex]\( x \)[/tex] that make [tex]\( 16 + 2x \)[/tex] divisible by 3 are [tex]\( x = 1 \)[/tex], [tex]\( x = 4 \)[/tex], and [tex]\( x = 7 \)[/tex].

Thus, the number of possible digits for [tex]\( x \)[/tex] such that [tex]\( 10x78x \)[/tex] is divisible by 3 is [tex]\( \boxed{3} \)[/tex].