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What is the solution of the matrix equation?

[tex]\[ \left[\begin{array}{ll}
1 & 2 \\
3 & 7
\end{array}\right]\left[\begin{array}{l}
x \\
y
\end{array}\right]=\left[\begin{array}{c}
10 \\
21
\end{array}\right] \][/tex]

A. [tex]\((30, -10)\)[/tex]

B. [tex]\((28, -9)\)[/tex]

C. [tex]\((26, -8)\)[/tex]

D. [tex]\((14, -2)\)[/tex]


Sagot :

To solve the matrix equation
[tex]\[ \begin{bmatrix} 1 & 2 \\ 3 & 7 \end{bmatrix} \begin{bmatrix} x \\ y \end{bmatrix} = \begin{bmatrix} 10 \\ 21 \end{bmatrix}, \][/tex]
we need to find the values of [tex]\(x\)[/tex] and [tex]\(y\)[/tex] that satisfy this equation. Here's a step-by-step approach:

1. Write the system of linear equations: The given matrix equation corresponds to the following system of linear equations:
[tex]\[ 1x + 2y = 10 \][/tex]
[tex]\[ 3x + 7y = 21 \][/tex]

2. Solve one of the equations for one variable: Let's solve the first equation for [tex]\(x\)[/tex]:
[tex]\[ x + 2y = 10 \Rightarrow x = 10 - 2y \][/tex]

3. Substitute this expression into the second equation:
[tex]\[ 3(10 - 2y) + 7y = 21 \][/tex]
Simplify this equation:
[tex]\[ 30 - 6y + 7y = 21 \Rightarrow 30 + y = 21 \][/tex]

4. Solve for [tex]\(y\)[/tex]:
[tex]\[ 30 + y = 21 \Rightarrow y = 21 - 30 \Rightarrow y = -9 \][/tex]

5. Substitute [tex]\(y\)[/tex] back into the expression for [tex]\(x\)[/tex]:
[tex]\[ x = 10 - 2y = 10 - 2(-9) = 10 + 18 = 28 \][/tex]

Thus, the solution to the matrix equation is:
[tex]\[ \begin{bmatrix} x \\ y \end{bmatrix} = \begin{bmatrix} 28 \\ -9 \end{bmatrix} \][/tex]

So, the correct choice is [tex]\((28, -9)\)[/tex]. Therefore, the answer is (28, -9).